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3 years ago

Please help me on this! Thank you!

Mathematics

1 answer:

Fantom [35]3 years ago

5 0

Answer:

The area of the garden is 17 yd^2

Step-by-step explanation:

Ok, let's divide the garden into 2 parts. The small part to the left of the patio let's call it area A. This area has 1 yd of width and 2 yd of length as it has the same length as the patio.

Therefore area A has an area of 1*2=2 yd

Let's call the remaining area area B.

We can see that its length is 3 yd and its width is 5 yd so:

3*5=15

Summing both areas to obtain the area of the garden we get

15+2=17

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2 years ago

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Gnesinka [82]

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3 years ago

In ΔEFG, the measure of ∠G=90°, GE = 32 feet, and EF = 41 feet. Find the measure of ∠E to the nearest tenth of a degree.

USPshnik [31]

Answer:

m∠E = 38.7°

Step-by-step explanation:

If you make a drawing it will help. What you have is a right triangle where you are given the adjacent side to ∠E and the hypotenuse.

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3 years ago

Read 2 more answers

Show that (0, 0) is equidistant from (1, 2), (-1, -2) and (2, 1).

Len [333]

Step-by-step explanation:

1) if (0;0) if point A, (1;2) is point B; (-1;-2) is C, (2;1) is D, then

2) the vector AB is (1;2); vector AC is (-1;-2) and vector AD is (2;1), then

3) the length of AB, AC and AD are:

$|AB|=\sqrt{1^2+2^2}=\sqrt{5};$

$|AC|=\sqrt{(-1)^2+(-2)^2}=\sqrt{5};$

$|AD|=\sqrt{2^2+1^2}=\sqrt{5}.$

4) if the lengths above are equal, then it means that (0, 0) is equidistant from (1, 2), (-1, -2) and (2, 1).

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2 years ago

For the given function, find the vertical and horizontal asymptotes f(x)= x2+3/ x2-9

Ratling [72]

Set the denominatior equal to zero to find vertical asymptotes. Horizontal take the highest degree of the top and divide it by the highest degree of the bottom.
${x}^{2} - 9 = 0 \\ {x}^{2} = 9 \\ x = 3 \\ x = - 3 \\ \\ \frac{ {x}^{2} }{ {x}^{2} } = 1 \\ y = 1$
Vertical: x=3, x=-3
Horizontal : y=1

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3 years ago