Student #4:

2 answers:

8 0

Answer:

I can’t see the graph but this student solved it incorrectly. When she divide both sides by -2, she should’ve flipped the sign.

Ugo [173]3 years ago

6 0

Flip the sign flip the sign because x isnt grater than 2

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A taxicab starts at (1, -2) on the grid. It goes 3 blocks east and 1 block south to pick up a passenger. Then it goes 6 blocks w

elena-14-01-66 [18.8K]

(x,y)
east is an increase in x
west is a decrease in x
north is an increase in y
south is a decrease in y

so
3 east (x+3)
1 block south (y-1)
6 blocks west (x-6)
5 blocks north (y+5)

so in total, x+3-6 and y-1+5
basically x-3 and y+4
minus 3 from and add 4 to y
(1,-2)
(1-3,-2+4)
(-2,2) is the dropoff point

8 0

4 years ago

The circle below has an area of 314 square centimeters, and the square inside the circle has a side length of 2 centimeters. A c

frez [133]

Answer:

31/40

Step-by-step explanation:

The question is incomplete. Here is the complete question with appropriate diagram.

The circle below has an area of 314 square centimeters, and the square inside the circle has a side length of 2 centimeters.

What is the probability that a point chosen at random is in the blue region?

Given the area of the circle to be 314cm², we need to get the diameter of the circle first since the diameter of the circle is equivalent to length of the side of the square inscribed in it.

Using the formula Area of a circle = πr²

314 = 3.14r²

r² = 314/3.14

r² = 100

r = 10 cm

Diameter of the circle = 2*10 = 20 cm

Area of a square = Length * length

Area of the outer square = 20*20 = 400cm²

Area of the inner square with side length 2cm = 2*2 =4cm²

Area of the shaded region = Area of the square - Area of the inner square

= 314-4 = 310cm²

The probability that a point chosen at random is in the blue region = Area of the shaded region/total area of the outer square