All categories

3 years ago

A dessert recipe calls for 2 1/2

Mathematics

1 answer:

shepuryov [24]3 years ago

6 0

Answer:

Step-by-step explanation:

A dessert recipe calls for 2 1/2cups of milk and makes 5 servings. How many cups of milk are needed for 6 servings?

If 2.5 cups of milk = 5servings

x =6 servings

x=(2.5×6)/5=3

For 6 servings, 3 cups of milk are needed

You might be interested in

Given the point (-3, 6) and a line y=2x-8, write an equation of a line through the point and parallel to the line.

ch4aika [34]

Answer: y = 2x

Step-by-step explanation:

The equation of a straight line can be represented in the slope intercept form as

y = mx + c

Where

m = slope = (change in the value of y in the y axis) / (change in the value of x in the x axis)

The equation of the given line is

y = 2x - 8

Comparing with the slope intercept form, slope = 2

If two lines are parallel, it means that they have the same slope. Therefore, the slope of the line passing through (- 3,-6) is 2

To determine the intercept, we would substitute m = 2, x = - 3 and

y = - 6 into y = mx + c. It becomes

- 6 = 2 × - 3 + c

- 6 = - 6 + c

c = - 6 + 6 = 0

The equation becomes

y = 2x

7 0

3 years ago

The radius of the large sphere is double the radius of the small sphere. How many times does the volume of the large sphere than

pshichka [43]

Answer:

8 times larger.

Step-by-step explanation:

The radius of the large sphere is double the radius of the small sphere.

Question asked:

How many times does the volume of the large sphere than the small sphere

Solution:

Let radius of the small sphere =  $x$ 

As the radius of the large sphere is double the radius of the small sphere:

Then, radius of the large sphere = $2x$

To find that how many times is the volume of the large sphere than the small sphere, we will divide the volume of large sphere by volume of small sphere:-

For smaller sphere: $Radius = x$

$Volume \ of \ sphere = \frac{4}{3} \pi r^{3}$

$=\frac{4}{3} \pi x^{3}$

For larger sphere: $Radius = 2x$

$Volume \ of \ sphere = \frac{4}{3} \pi r^{3}$

$=\frac{4}{3} \pi (2x)^{3}$

Now, we will divide volume of the larger by the smaller one:

$=\frac{4}{3} \pi (2x)^{3}\div\frac{4}{3} \times\frac{\pi }{1 } \times x^{3}\\ \\ =\frac{4}{3} \pi\times8x^{3} \times\frac{3}{4\pi }\ \times\frac{1}{x^{3} }$