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Naddika [18.5K]
3 years ago
12

PLS HELP: Identify the correct CSS syntax to link an external style sheet??

Computers and Technology
1 answer:
kupik [55]3 years ago
5 0

Answer:

See Explanation

Explanation:

This question required options. Since there are none, I'll answer on a general terms.

To link to an external style sheet in CSS, use the following syntax:

<link rel = "stylesheet" type = "text/css" href = "link to css file">

As seen above, the link tag is used to achieve this tax.

The rel attributes shows the relationship between the css file and the html file.

In this case, the css file is a stylesheet; hence, rel = "stylesheet"

Next, is the type attribute which shows the content of the file to be linked. In other words, the file type

Lastly, the link to the css file.

Take for instance, the file name is example.css and it is in the same directory as the current document, the following will be used.

href = "example.css"

<em>However, if example.css is in a different directory, the link to the file directory will be stated.</em>

<em></em>

Conclusively, one syntax to use for a file named example.css is:

<em><link rel = "stylesheet" type = "text/css" href = "exampl.css"></em>

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How do programmers recognise patterns, generalise and abstract information
Dima020 [189]

Answer:

Pattern recognition is the process of recognizing patterns by using machine learning algorithm. ... In a typical pattern recognition application, the raw data is processed and converted into a form that is amenable for a machine to use. Pattern recognition involves classification and cluster of patterns

Explanation:

4 0
3 years ago
Create a class called Hokeemon that can be used as a template to create magical creatures called Hokeeemons. Hokeemons can be of
Viefleur [7K]

Answer:

See Explaination

Explanation:

/*****************************************Hokeemon.java********************************/

import java.io.File;

import java.io.FileNotFoundException;

import java.util.Scanner;

public class Hokeemon {

private String name;

private String type;

private int age;

public Hokeemon(String name, String type, int age) {

super();

this.name = name;

this.type = type;

this.age = age;

}

public Hokeemon() {

this.name = "";

this.type = "";

this.age = 0;

}

public String getName() {

return name;

}

public void setName(String name) {

this.name = name;

}

public String getType() {

return type;

}

public void setType(String type) {

this.type = type;

}

public int getAge() {

return age;

}

public void setAge(int age) {

this.age = age;

}

public String liveIn() {

if (this.type.equalsIgnoreCase("dwarf")) {

return "Mountain";

} else if (this.type.equalsIgnoreCase("elf")) {

return "Dale";

} else if (this.type.equalsIgnoreCase("fairy")) {

return "Forest";

} else {

return "Shire";

}

}

public boolean areFriends(Hokeemon other) {

if (this.type.equalsIgnoreCase(other.type)) {

return true;

} else if ((this.type.equalsIgnoreCase("dwarf") && other.type.equalsIgnoreCase("elf"))

|| (this.type.equalsIgnoreCase("elf") && other.type.equalsIgnoreCase("dwarf"))) {

return true;

} else if ((this.type.equalsIgnoreCase("hobbit") && other.type.equalsIgnoreCase("fairy"))

|| (this.type.equalsIgnoreCase("fairy") && other.type.equalsIgnoreCase("hobbit"))) {

return true;

} else {

return false;

}

}

public static Hokeemon[] getData(String file) {

Hokeemon[] hokeemons = new Hokeemon[8];

int i = 0;

try {

Scanner scan = new Scanner(new File(file));

while (scan.hasNextLine() && i < hokeemons.length) {

String line = scan.nextLine();

String[] data = line.split("\\s+");

String name = data[0];

String type = data[1];

int age = Integer.parseInt(data[2]);

hokeemons[i] = new Hokeemon(name, type, age);

i++;

}

scan.close();

} catch (FileNotFoundException e) {

System.err.println(e);

}

return hokeemons;

}

public static String getBio(Hokeemon[] hokeemons) {

String s = "";

for (Hokeemon hokeemon : hokeemons) {

s += "I am " + hokeemon.getName() + ": Type " + hokeemon.getType() + ": Age=" + hokeemon.getAge()

+ ", I live in " + hokeemon.liveIn() + "\n";

s += "My friends are: ";

for (Hokeemon hokeemon2 : hokeemons) {

if (hokeemon.areFriends(hokeemon2) && !hokeemon.equals(hokeemon2)) {

s += (hokeemon2.getName() + " ");

}

}

s += "\n";

}

return s;

}

atOverride

public String toString() {

return "Name " + name + ": Type " + type + ": Age=" + age + "\n";

}

}

/*******************************HokeemonMain.java**************************/

import java.util.Arrays;

public class HokeemonMain {

public static void main(String[] args) {

Hokeemon[] hokeemons = Hokeemon.getData("data.txt");

System.out.println(Arrays.toString(hokeemons));

System.out.println(Hokeemon.getBio(hokeemons));

}

}

/**********************************data.txt********************/

Noddy Dwarf 4

Legolas Elf 77

Minerva Fairy 33

Samwise Hobbit 24

Merry Hobbit 29

Warhammer Dwarf 87

Ernedyll Elf 19

Frodo Hobbit 18

3 0
4 years ago
Find the equation of a line which has 10 points the following two coordinates: (4, 0) and (3, 4)​
alex41 [277]

Answer:

The equation of the line is y = -4·x + 16

10 points on the line include;

(0, 16), (1, 12), (2, 8), (3, 4), (4, 0), (5, -4), (6, -8), (7, 12), (8, -16), (9, -20), and (10, -24)

Explanation:

The given points through which the line passes are;

(4, 0) and (3, 4)

The slope, 'm', of the line is given as follows;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

Therefore, the slope of the line is (4 - 0)/(3 - 4) = -4

In point and slope form we can get;

\dfrac{y-0}{x-4} = -4

The equation of the line in point and slope form is therefore;

y = -4·(x - 4) = -4·x + 16

The equation of the line in slope and intercept form is

y = -4·x + 16

10 points on the line are obtained using the equation of the line and the desired x-values input into cells on MS Excel and presented here as follows;

(0, 16), (1, 12), (2, 8), (3, 4), (4, 0), (5, -4), (6, -8), (7, 12), (8, -16), (9, -20), and (10, -24)

8 0
3 years ago
What properties make it suitable to be used for musical instruments?
Stolb23 [73]
<h2>Many properties can be listed out viz. durability, quality, the sound that it produces also depends on the material that is used, etc.</h2>

Explanation:

1. If you take wood then I would say maple, rosewood, cedar, walnut can be used to make "String instruments".

Reason:

The wood that we choose should be perfect and should give long-life to use the instrument.

2. If we consider about strings, then I would suggest that the material that you choose should be "ductile and hard".

Reason:

Thin wires can be drawn.

3. In case of Brass, it should be "malleable metal", so that the outcome of the instrument will satisfy the need.

7 0
4 years ago
Which one of the following is malicious software that denies you access to your files or your organization's files unless you pa
gladu [14]

Answer:

Ransomware

Explanation:

Just as its name implies, you have to pay a 'ransom' to get a locked file that  belongs to you

4 0
2 years ago
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