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AnnyKZ [126]
3 years ago
5

How does the autosum command calculate data? Need help ASAP​

Computers and Technology
1 answer:
Verizon [17]3 years ago
8 0

Answer:

mjhkjdbc.xmbvmn xz

Explanation:

xjkbvkjshdkjvn.hlxnhc

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A particularly devastating type of dos attack is the ____ dos attack, in which multiple unsuspecting computers are used to attac
IgorLugansk [536]
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3 0
3 years ago
A popular game allows for in-app purchases to acquire extra lives in the game. When a player purchases the extra lives, the numb
Taya2010 [7]

Based on the fact that the hacker's actions are done before the application reading of the lives purchased, this is <u>d. Race condition. </u>

<h3>What is a race condition?</h3>

This is when certain processes in an application depend on the timing of a a previous process or event. The flow of information can then be intercepted before the process completes.

This is what the hacker did here by accessing the application to change the number of lives purchased before the application read the number of lives purchased.

In conclusion, option D is correct.

Find out more on the race condition at brainly.com/question/13445523.

4 0
2 years ago
You need to connect two computers for a customer. The customer does not have a network and does not wish to purchase a concentra
SIZIF [17.4K]

Answer:

Crossover Cable

Explanation:

In networking, If two computers have same specifications and need to be connected then the only thing that is required is known as crossover cable. This cable is used to connect two computer of same types without using hub or switch.

7 0
3 years ago
If you have 128 oranges all the same size, color, and weight except one orange is heavier than the rest. Write down a C++ Code t
dangina [55]

Answer:

#include <iostream>

using namespace std;

void Search_heavy_orange(int arr[], int l, int r, int x)

{

int count = 0, m = 0;

while (l <= r) {

 m = l + (r - l) / 2;

 // Check if x is present at mid

 if (arr[m] == x) {

  count++;

 }

 // If x greater, ignore left half

 if (arr[m] < x) {

  l = m + 1;

  count++;

   

 }

 

 // If x is smaller, ignore right half

 else {

  r = m - 1;

  count++;

 }

}

cout << "............For Worst Case......." << endl;

cout << "Orange with heavy weight is present at index " << m << endl;

cout << "Total number of step performed : " << count << endl;

}

int main()

{

// Assuming each orange is 100 gm and the weight of heavy

// orange is 150 gm

int orange_weight[128];

for (int i = 0; i < 127; i++) {

 orange_weight[i] = 100;

}

// At worst case the heavy orange should be at last position

// inside the basket : 127

orange_weight[127] = 150;

// We will pass array , start index , last index and the search element

// as the parameters in the function Search_heavy_orange

Search_heavy_orange(orange_weight, 0, 127, 150);

return 0;

}

Explanation:

this is it. it display for the worst case

3 0
3 years ago
In function main prompt the user for a time in seconds. Call a user defined function to calculate the equivalent time in hours,
Molodets [167]

Answer:

#include <iostream>

#include <cmath>

using namespace std;

int main()

{

   cout<<"Enter time in seconds:";

   int time, hour, minutes, seconds,initialTime;

   

   cin>>time;

   initialTime = time;

   

   hour = floor(time / 3600);

   time = time % 3600;

   minutes = floor(time / 60);

   time = time % 60;

   seconds = time;

   cout<< initialTime<<" can be broken down into: "<<endl;

   cout<<hour << " hour(s)"<<endl;

   cout<<minutes <<" minutes"<<endl;

   cout<<seconds <<" seconds"<<endl;

   return 0;

}

Explanation:

The programming language use is c++

The module cmath was called to allow me perform some math operations like floor division, and the Iostream allows me to print output to the screen. Using namespace std allows me to use classes from the function std.

I prompt the user to enter time in second, then declare all the variables that will be used which include time, hour, minutes, seconds and initialTime.

initialTime is used to hold the the time input entered by the user and will be printed at the end no arithmetic operation is carried out on it.

Floor division (returns the quotient in a division operation) and Modulo (returns the remainder in a division operation) division is used to evaluate the hours, the minutes and the seconds.

The final answers are then printed to the screen.

I have uploaded the c++ file and a picture of the code in action

4 0
3 years ago
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