How does the autosum command calculate data? Need help ASAP

Pick the 3 correct Python functions that parse and output only the date and time part of each log in log.txt as follows.

Mila [183]

Answer:

1, 4, 5

Explanation:

parse2:

. In this case it's passing "r" as an argument, which really does absolutely nothing, because whenever you call open("file.txt") it defaults to reading mode, so all you're doing is explicitly passing the "r". So let's look at the first line. Whenever you call str.split() without any arguments, by default it splits it by empty text, and filters any empty text. So str.split() is not the same as str.split(" ") although it has similar behavior. " ".split(" ") will output ['', '', '', '', '', ''], while " ".split() will output []. So in this case the line.split() will split the string '10.1.2.1 - car [01/Mar/2022:13:05:05 +0900] "GET /python HTTP/1.0" 200 2222' into the list ['10.1.2.1', '-', 'car', '[01/Mar/2022:13:05:05', '+0900]', '"GET', '/python', 'HTTP/1.0"', '200', '2222']. As you can see the the data is split into two pieces of text, AND they include the brackets in both strings. So when it gets the 3 index and strips it of the "[]" it will have the incomplete date

parse3:

In this instance the "r" does nothing as mentioned before the "r" is already defaulted whenever you call open("file.txt") so open("file.txt") is the same as open("file.txt", "r"). So in this case we won't be working left to right, we're going inside the brackets first, kind of like in math you don't don't work left to right in equation 3 + 3(2+3). You work in the brackets first (inside brackets you do left to right). So the first piece of code to run is the line.split("[" or "]"). I actually kind of misspoke here. Technically the "[" or "]" runs first because this doesn't do what you may think it does. The or will only return one value. this is not splitting the line by both "[" and "]". The, or will evaluate which is true from left to right, and if it is true, it returns that. Since strings are evaluated on their length to determine if they're true. the "[" will evaluate to true, because any string that is not empty is true, if a string is empty it's false. So the "[" will evaluate to true this the "[" or "]" will evaluate to "[". So after that the code will run line.split("[") which makes the list: ['10.1.2.1 - car ', '01/Mar/2022:13:05:05 +0900] "GET /python HTTP/1.0" 200 2222']. Now the [3:5] will splice the list so that it returns a list with the elements at index 3 (including 3) to 5 (excluding 5). This returns the list: [], because the previous list only has 2 elements. There are no elements at index 3 to 5 (excluding 5). So when you join the list by " ", you'll get an empty string

parse4:

So I'm actually a bit confused here, I thought the "r+" would open the file in read-writing mode, but maybe this is a different version of python I have no idea, so I'm going to assume it is reading/writing mode, which just means you can read and write to the file. Anyways when you split the line by doing line.split(), as mentioned before it will split by empty spaces and filter any empty spaces. This line will return: ['10.1.2.1', '-', 'car', '[01/Mar/2022:13:05:05', '+0900]', '"GET', '/python', 'HTTP/1.0"', '200', '2222']. and then you splice the list from indexes 3 to 5 (excluding 5). This will return the list: ['[01/Mar/2022:13:05:05', '+0900]'] which has the two pieces of information you need for the date. Now it joins them by a space which will output: '[01/Mar/2022:13:05:05 +0900]'. Now when you strip the "[]" you get the string: '01/Mar/2022:13:05:05 +0900' which is the correct output!

parse 5:

So in this example it's using re.split. And the re.split is splitting by "[" or "]" which is what re.split can be used for, to split by multiple strings, which may be confused by string.split("[" or "]") which is not the same thing as explained above what the latter does. Also the reason there is a backslash in front of the [ and ] is to escape it, because normally those two characters would be used to define a set, but by using a \ in front of it, you're essentially telling regex to interpret it literally. So in splitting the string by "[" and "]" you'll get the list: ['10.1.2.1 - car ', '01/Mar/2022:13:05:05 +0900', ' "GET /python HTTP/1.0" 200 2222'] which has 3 elements, since it was split by the [ and the ]. The second element has the date, so all you need to do is index the list using the index 1, which is exactly what the code does

8 0

2 years ago

In 4-bit two's complement representation, what is the binary encoding of the number -5?

Katena32 [7]

Answer:

a) 1011

Explanation:

In 4 bit two's complement representation, the first bit is the sign bit.

If the sign bit is 1, the number is negative.

If the sign bit is 0, the number is positive.

What is the magnitude of the sign bit?

In n-bit two's complement representation, the magnitude of the sign bit is:

$2^{n-1}-1$

So, in 4-bit two's complement representation, the magnitude of the sign bit is:

$2^{4-1}-1 = 8$

Since the number is negative, the value of this bit is -8.

The other bits are magnitude bits, positive.

We have that the sum of these bits must be -5, and we already have -8. So what should be the value of these last 3 bits?

First, i am going to solve this equation to find the decimal value of the last three bits.

$-5 = -8 + x$

$x = 3$

So, the last three bits are:

$3_{10} = (011)_{2}$

The binary encoding of the number -5 is:

a) 1011

5 0

3 years ago

Your sister is starting 9th grade next year and is thinking about going to college. What step would you recommend she take first

lozanna [386]

think about what she wants to do with her life and what collage is best fit for that

5 0

3 years ago

Read 2 more answers

Funny or fascinating web content is said to go _________ when it is shared and re-shared a large number of times over a short pe

beks73 [17]

It is said to go viral?

4 0

3 years ago

Write a program that accepts an integer value called multiplier as user input. Create an array of integers with ARRAY_SIZE eleme

Tasya [4]

Answer:

The program in C++ is as follows:

#include <iostream>

using namespace std;

void PrintForward(int myarray[], int size){

for(int i = 0; i<size;i++){ cout<<myarray[i]<<" "; }

}

void PrintBackward(int myarray[], int size){

for(int i = size-1; i>=0;i--){ cout<<myarray[i]<<" "; }

}

int main(){

const int ARRAY_SIZE = 12;

int multiplier;

cout<<"Multiplier: ";

cin>>multiplier;

int myarray [ARRAY_SIZE];

for(int i = 0; i<ARRAY_SIZE;i++){ myarray[i] = i * multiplier; }

PrintForward(myarray,ARRAY_SIZE);

PrintBackward(myarray,ARRAY_SIZE);

return 0;}

Explanation:

The PrintForward function begins here

void PrintForward(int myarray[], int size){

This iterates through the array in ascending order and print each array element

for(int i = 0; i<size;i++){ cout<<myarray[i]<<" "; }

}

The PrintBackward function begins here

void PrintBackward(int myarray[], int size){

This iterates through the array in descending order and print each array element

for(int i = size-1; i>=0;i--){ cout<<myarray[i]<<" "; }

}

The main begins here

int main(){

This declares and initializes the array size

const int ARRAY_SIZE = 12;

This declares the multiplier as an integer

int multiplier;

This gets input for the multiplier

cout<<"Multiplier: "; cin>>multiplier;

This declares the array

int myarray [ARRAY_SIZE];

This iterates through the array and populate the array by i * multiplier

for(int i = 0; i<ARRAY_SIZE;i++){ myarray[i] = i * multiplier; }

This calls the PrintForward method

PrintForward(myarray,ARRAY_SIZE);

This calls the PrintBackward method

PrintBackward(myarray,ARRAY_SIZE);

return 0;}

6 0

3 years ago

How does the autosum command calculate data? Need help ASAP​

How does the autosum command calculate data? Need help ASAP