This can be seen through the fact that Aksionov has the ability to seek his own justice many times throughout the story, yet does not take it
Answer:
v = 120 m/s
Explanation:
We are given;
earth's radius; r = 6.37 × 10^(6) m
Angular speed; ω = 2π/(24 × 3600) = 7.27 × 10^(-5) rad/s
Now, we want to find the speed of a point on the earth's surface located at 3/4 of the length of the arc between the equator and the pole, measured from equator.
The angle will be;
θ = ¾ × 90
θ = 67.5
¾ is multiplied by 90° because the angular distance from the pole is 90 degrees.
The speed of a point on the earth's surface located at 3/4 of the length of the arc between the equator and the pole, measured from equator will be:
v = r(cos θ) × ω
v = 6.37 × 10^(6) × cos 67.5 × 7.27 × 10^(-5)
v = 117.22 m/s
Approximation to 2 sig. figures gives;
v = 120 m/s
Answer:second class lever needs less force to lift a load
Explanation: because the load is between the fulcrum/pivot point and the force. The fulcrum is far away from the force
The mass is 7.81 kilograms
Answer:
Velocity of the wave is 1.7 m/s
Explanation:
As we know that the frequency of the wave is defined as the number of waves crossing a fixed point per second
So here we will have
Also we know that the distance between two consecutive crest or two consecutive trough is known as wavelength
So here the wavelength of the wave is given as
now we have
