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4 years ago

A fisherman sees 7 wave crests

Physics

1 answer:

insens350 [35]4 years ago

4 0

Answer:

Velocity of the wave is 1.7 m/s

Explanation:

As we know that the frequency of the wave is defined as the number of waves crossing a fixed point per second

So here we will have

$f = \frac{N}{t}$

$f = \frac{7}{10} = 0.7 Hz$

Also we know that the distance between two consecutive crest or two consecutive trough is known as wavelength

So here the wavelength of the wave is given as

$\lambda = 2.43 m$

now we have

$v = \lambda \times f$

$v = (2.43 \times 0.7)$

$v = 1.7 m/s$

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If a car has a velocity of 85 km/hr, how long will it take to accelerate to 45 km/hr if the acceleration is -3 km/hr/sec?

weqwewe [10]

Answer:

Time, t = 13.34 seconds.

Explanation:

Given the following data;

Initial velocity, u = 85km/hr to meters per seconds = 85*1000/3600 = 23.61 m/s

Final velocity, v = 45km/hr to meters per seconds = 45*1000/3600 = 12.5 m/s

Acceleration, a = -3 km/hr/sec to meters per seconds square = -3*1000/3600 = -0.833m/s²

To find the time;

Acceleration = (v - u)/t

-0.833 = (12.5 - 23.61)/t

-0.833t = -11.11

t = 11.11/0.833

Time, t = 13.34 seconds.

6 0

3 years ago

If you travel 5 miles north then turn and travel 5 miles south, you are now _____ miles from where you started.

horsena [70]

0 miles from where you started

3 0

3 years ago

Read 2 more answers

The angle θ is slowly increased. Write an expression for the angle at which the block begins to move in terms of μs.

Reika [66]

Answer:

$tan \theta = \mu_s$

Explanation:

An object is at rest along a slope if the net force acting on it is zero. The equation of the forces along the direction parallel to the slope is:

$mg sin \theta - \mu_s R =0$ (1)

where

$mg sin \theta$ is the component of the weight parallel to the slope, with m being the mass of the object, g the acceleration of gravity, $\theta$ the angle of the slope

$\mu_s R$ is the frictional force, with $\mu_s$ being the coefficient of friction and R the normal reaction of the incline

The equation of the forces along the direction perpendicular to the slope is

$R-mg cos \theta = 0$

where

R is the normal reaction

$mg cos \theta$ is the component of the weight perpendicular to the slope

Solving for R,

$R=mg cos \theta$

And substituting into (1)

$mg sin \theta - \mu_s mg cos \theta = 0$

Re-arranging the equation,

$sin \theta = \mu_s cos \theta\\\rightarrow tan \theta = \mu_s$

This the condition at which the equilibrium holds: when the tangent of the angle becomes larger than the value of $\mu_s$ , the force of friction is no longer able to balance the component of the weight parallel to the slope, and so the object starts sliding down.

4 0

4 years ago

2. A student was sitting on one end of a set of metal bleachers outside of a school building. A drumline was practicing on the o

matrenka [14]

The students can feel the vibrations from the bleachers, but not from the drums because of the resonance.

<h3>What is the resonance?</h3>

The resonance condition occurs when the frequency of a wave matches with the resonance frequency.

The transfer of energy becomes maximum when the natural frequency matches with the frequency generated by the source.

The bleacher and student together having the frequency matching with the resonance frequency of the drum.

The bleacher and student with the bag frequency doesn't match with the resonance value of drums. Secondly, as distance increases sound intensity also decreases.

Thus, the student can feel the vibrations from the bleachers, but not from the drums because of the resonance.

Learn more about resonance.

brainly.com/question/15337338

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6 0

2 years ago

Suppose that you hear a clap of thunder 16.2 s (seconds) after seeing the associated lightning stroke. The speed of sound waves

spayn [35]

Since the speed of sound is very high, we consider the time period of thunder and lightening negligible.

Now, d = vt

thus, d = 343 x 16.2

thus, d = 5556.6 metres

Thus, we are 5556.6 metres away from lightening ( approximately)

5 0

3 years ago