Please help me fast

Physics

1 answer:

hjlf2 years ago

5 0

Wolffia

I think I know that is the smallest flowering plant, but I don’t know about just the smallest plant.

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If the absolute temperature of a gas is 600 K, the temperature in degrees Celsius is

gavmur [86]

Kelvin is a base unit of temperature scale from SI that defines as zero degree Kelvin (absolute zero). The absolute zero is a hypothetical statement that all molecular movement stops because there is no transient of energy for the molecules to move. When converting temperature in degree Celsius to Kelvin, add 273. You are given 600K and you are asked to find it in degrees Celsius.

T(K) = T(C) + 273
600 K = T(C) + 273
T(C) = 600 – 273
T(C) = 327 °C
The answer is letter B.

6 0

3 years ago

Read 2 more answers

If a planet has 3 times the radius of the Earth, but has the same density as the Earth, what is the gravitational acceleration a

xz_007 [3.2K]

Answer:

The Gravitational Acceleration of the Big planet is G = 3g

where G is the gravitational acceleration of the Big Planet and g is the gravitational acceleration of the Earth

So, it becomes G = 3 x 9.8 $ms^{-2}$

G = 29.4 $ms^{-2}$

Explanation:

Let's start by calculating the Density of the Earth of mass m anad Radius r

We know that mass is density times the volume

ρ = $\frac{m}{V}$

m = ρV

we know the volume is V = $\frac{4}{3}$ $πr^{3}$ (please ignore the symbol of Pi)

m = ρ $\frac{4}{3}$ $πr^{3}$

Calculating the Density of Big Planet

→For Big Planet we know that radius is 3-times the radius of Earth, that is 3r

M = ρ $\frac{108}{3}$ $π(r)^{3}$

So in conclusion, the mass of Earth and the mass of Big planet are related as M = 27m

Now let's come to the Gravitational Force, we know that gravitational force is directly proportional to the mass of the body and inversely proportional to the radius.

→Suppose for Earth: Mass = m, Radius = r

For Big Planet: Mass = M, Radius = R

$\frac{m}{r^{2} }$ : $\frac{M}{R^{2} }$ = g : G