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2 years ago

11

A house cat weighs 9.22 pounds Hercules the liger is the worlds largest cat and weighs 100 times the weight of the house cat how

much more does Hercules weigh than the house cat

1 answer:

Tanya [424]2 years ago

5 0

Answer:

922 pounds

Step-by-step explanation:

9.22 x 100 = 922

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you pay 3.3 cents per minute for long-distance phone calls on your phone. your phone bill is $3.40 write and solve an equation t

MaRussiya [10]

If you would like to know the number of minutes of long-distance calls you made, you can calculate this using the following steps:

3.3 cents = $0.033
m = $3.40 / 3.3 cents
m = $3.40 / $0.033 = 3.40 / 0.033
m = 103.03 minutes

The correct result would be <span>103.03 minutes.</span>

5 0

2 years ago

If Joe drives 186.83 miles on a business trip, and the reimbursement from his company is $13.08. At what rate is Joe's employer

kirill115 [55]

Answer:

7 cents/mile

Step-by-step explanation:

You are looking for a unit rate of cents per mile.

Change the dollar amount to cents, and divide by the number of miles.

$13.08 * (100 cents)/$ = 1308 cents

(1308 cents)/(183 miles) = 7.001 cents/mile

8 0

2 years ago

Select all that apply.

kkurt [141]

Sample space, The counting Principle and, a table can be used

7 0

3 years ago

42.6 is 66 2/3% of what number?

Elza [17]

42.6 is 66 2/3% of 63.9

the answer is : 63.9

4 0

3 years ago

The points A BC :(2, 2,1), :(1,1,3), :(2,0,5) − are the vertices of a right triangle. The radius of the sphere with center at th

ElenaW [278]

Answer:

r=1

Step-by-step explanation:

First we need to know the length of each side of the triangle, so we use the formula of the vector modulus:

$|AB|= \sqrt{(b_{1}-a_{1})^{2}+(b_{2}-a_{2})^{2}+(b_{3}-a_{3})^{2}$

By doing so, we find:

$|AB|=\sqrt {6}\\|BC|=\sqrt {6}\\|AC|=2\sqrt {5}$

With this we know that the triangle is not right, but, we assume the longest side as the hypotenuse of the problem.

As we have two equal sides, we know that the line between point |AB| and the center of the hypotenuse is perpendicular, therefore, we can calculate it using Pythagoras theorem:

$|BC|^{2}=r^{2}+(\frac{|AC|}{2})^{2}\\\\r^{2}=|BC|^{2}-(\frac{|AC|}{2})^{2}\\\\r^{2}=(\sqrt{6})^{2}- (\frac{2\sqrt{5}}{2})^{2}\\\\r^{2}=6-5=1\\r=1$

4 0

2 years ago