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3 years ago

Four decreased by the product of a number and 7 is equal to 11

Mathematics

2 answers:

Vilka [71]3 years ago

6 0

Answer:

$y=2\frac{1}{7}$

Step-by-step explanation:

(y · 7) - 4 = 11

7y - 4 = 11

7y - 4 + 4 = 11 + 4

7y = 15

7y ÷ 7 = 15 ÷ 7

$y=2\frac{1}{7}$

Nana76 [90]3 years ago

5 0

Answer:

See image below:)

Step-by-step explanation:

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4 years ago

One container is filled with mixture that is 25% acid. A second container is filled with a mixture that is 55% acid. The second

algol13

Answer:

Therefore the third container contains $\frac{735}{17}\%$ = 43.23 % acid.

Step-by-step explanation:

Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.

Let the volume of first container be x cubic unit.

Since the volume of second container is 55% larger than the first.

Then the volume of the second container is

$= (V\times \frac{100+55}{100})$ cubic unit.

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$=(\frac{155}{100}V \times \frac{55}{100})$ cubic unit.

$=\frac{8525}{10000}V$ cubic unit.

Total amount of acid $=(\frac{25}{100}V+\frac{8525}{10000}V)$ cubic unit.

$=(\frac{2500+8525}{10000}V)$ cubic unit.

$=(\frac{11025}{10000}V)$ cubic unit.

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$=\frac{100+155}{100}V$ cubic unit.

$=\frac{255}{100}V$ cubic unit.

The amount of acid in the mixture is

$=\frac{\textrm{The volume of acid}}{\textrm{The amount of mixture}}\times 100 \%$

$=\frac {\frac{11025}{10000}V}{\frac{255}{100}V}\times 100\%$

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Therefore the third container contains $\frac{735}{17}\%$ acid.

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3 years ago

Solve the following system using substitution

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Change x+y=5 to y=5-x
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3 years ago

Read 2 more answers

Please help with this question ASAP!!!! Will give brainliest

alexandr402 [8]

All you have to do is multiply 23/4 by 4/3 which gets you 92/12

Simplify that and you get 23/3

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3 years ago