Given
Height (length) of the anchor dropped from the boat = 75 feet
Distance of the treasure from the anchor = 40 feet
Solution
The dropped at the bottom makes an angle of 90 degree . Therefore making an right triangle with the chest and boat
By Pythagoras theorem
AC^2 = AB^2 + BC^2
(AC = distance of the treasure from the boat
AB = height of the anchor dropped from the boat
BC = the distance of treasure from the anchor)
AC^2 = 75^2 + 40^2
AC^2 = 5325 +1600
AC^2 = 6925
AC = 25 * (under root 11)
Therefore they have cover a distance of 25 * (under root 11)
Answer:
The answer is 92cm wide.
Step-by-step explanation:
Answer:
192
Step-by-step explanation:
Ratio : 3:7:8
Let the amount with Ahmad, Hassan and Shahril be 3x,7x and 8x
7x - 3x = 96
4x = 96
x = 96/4
x= 24
Amount donated by Shahril = 8x = 8 *24 = 192
