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mart [117]
3 years ago
10

Martina read that the average graduate student is 33 years old. She wanted to estimate the mean age of graduate students at her

large university, so she took a random sample of 30 graduate students. What is Martina's margin of error?
Mathematics
1 answer:
Bogdan [553]3 years ago
8 0

Answer: Martina's margin of error is 1.5.

Step-by-step explanation:

Given: Average graduate student (upper limit) = 33

Random sample graduate student (lower limit) = 30

Formula to calculate margin of error is as follows.

Margin of error = \frac{upper limit - lower limit}{2}

Substitute the values into above formula as follows.

Margin of error = \frac{upper limit - lower limit}{2}\\= \frac{33 - 30}{2}\\= \frac{3}{2}\\= 1.5

Thus, we can conclude that Martina's margin of error is 1.5.

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Answer:

The average speed over the time interval from 9 A.M. to noon was of 33.33 mph.

Step-by-step explanation:

The average speed is given by the following equation:

v = \frac{d}{t}

From 10A.M. to noon.

You traveled at 50mph during 2 hours. So how long you traveled?

50 = \frac{d}{2}

d = 50*2

d = 100

You traveled 100 miles.

What was your average speed over the time interval from 9 A.M. to noon

From 9 A.M. to 10 A.M, you did not travel.

From 10 P.M. to noon, 100 miles.

So 100 miles during 3 hours.

v = \frac{d}{t} = \frac{100}{3} = 33.33

The average speed over the time interval from 9 A.M. to noon was of 33.33 mph.

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3 years ago
Is the function f(x)=12x3 even or odd? Why?
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Seven students each picked 88 flowers. How many flowers did they pick altogether?
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Step-by-step explanation:

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200 people purchase a lottery ticket. Three winning tickets will be selected at random. If first prize is $100, second prize is
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Mary must choose a new password where the first and last choices are possibly repeated lowercase letters; the second and third
Salsk061 [2.6K]

The number of ways she can choose a password is 3986236800

<h3>In how many ways can she choose a password?</h3>

The given parameters and the possible selection of characters are:

First and last choices are possibly repeated lowercase letters;

There are 26 lower characters.

Since the characters can be repeated, then we have

First = 26

Last = 26

The second and third positions must be distinct uppercase letters

There are 26 upper characters.

Since the characters are distinct, then we have

Second = 26

Third = 25

The fourth position must be a # , $, or & symbol;

So, we have

Fourth = 3

The next four positions are distinct nonzero digits.

There are 9 nonzero digits.

Since the digits are distinct, then we have

Next = 9, 8, 7, 6

The number of ways she can choose a password is

Ways = First * Second * Third * Fourth * Next * Last

So, we have

Ways = 26 * 26 * 25 * 3 * 9 * 8 * 7 * 6 * 26

Evaluate the product

Ways = 3986236800

Hence, the number of ways she can choose a password is 3986236800

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