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jasenka [17]
3 years ago
15

Your plan was to be on the road by 9 A.M. but you did not leave the garage until 10 A.M. You then drove with the cruise control

set at 50 mph until stopping at noon. What was your average speed over the time interval from 9 A.M. to noon
Mathematics
1 answer:
Wittaler [7]3 years ago
8 0

Answer:

The average speed over the time interval from 9 A.M. to noon was of 33.33 mph.

Step-by-step explanation:

The average speed is given by the following equation:

v = \frac{d}{t}

From 10A.M. to noon.

You traveled at 50mph during 2 hours. So how long you traveled?

50 = \frac{d}{2}

d = 50*2

d = 100

You traveled 100 miles.

What was your average speed over the time interval from 9 A.M. to noon

From 9 A.M. to 10 A.M, you did not travel.

From 10 P.M. to noon, 100 miles.

So 100 miles during 3 hours.

v = \frac{d}{t} = \frac{100}{3} = 33.33

The average speed over the time interval from 9 A.M. to noon was of 33.33 mph.

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3 years ago
One eighth of a number is ten less than one third of the number. Find the number.
GarryVolchara [31]
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bring the values with the variable on one side

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find a common denominator and subtract these fractions

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7 0
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irina1246 [14]
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3 years ago
What measurement is equal to 6 kg
kompoz [17]

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6 0
3 years ago
Help!!!!!!!!!!!!!!!!!!!!
lapo4ka [179]
Well...   the segment FG = 4x + 3, the segment GH = 7x - 12, now, the
 
segment FH = FG + GH, those two fellows added up, and we know that FG and GH are both equal halves because G is the midpoint.

thus, FG = GH
or

\bf 4x+3=7x-12\implies 3+12=7x-4x\implies 15=3x
\\\\\\
\cfrac{15}{3}=x\implies \boxed{5=x}\\\\
-------------------------------\\\\
thus\qquad 
\begin{cases}
\overline{FG}=4x+3\\
4(5)+3\\
23\\
------\\
\overline{GH}=7x-12\\
7(5)-12\\
23
\end{cases}\impliedby equal\ halves
\\\\\\
\overline{FH}=23+23\implies \overline{FH}=46\implies 6y-2=46
\\\\\\
6y=46+2\implies y=\cfrac{48}{6}

and fairly sure, you know how much that is.
7 0
3 years ago
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