Ask question

Ask question

All categories

marishachu [46]

3 years ago

9

A random generated list of numbers from 0 to 4 is being used to simulate an event, with the numbers 3 and 4 representing a succe

ss. what is the estimated probability of a success?
A. 60%
B. 40%
C. 25%
D. 75%

1 answer:

Sloan [31]3 years ago

6 0

Since there are 5 numbers 0-4 and there are 2 numbers that is a success. The probability is 2/5 or 40% or B.

You might be interested in

Trigonometric Identities

bogdanovich [222]

$\bf \textit{symmetry identities}\\\\
sin(-\theta )\implies -sin(\theta )\qquad \qquad cos(-\theta )\implies cos(\theta )
\\\\\\also~recall\\\\ sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)
\\\\\\
sin^2(\theta)=1-cos^2(\theta)
\\\\
-------------------------------\\\\\
[1-cos(-t)][1+cos(t)]\implies [1-cos(t)][1+cos(t)]$

$\bf 1^2-cos^2(t)\implies 1-cos^2(t)\implies sin^2(t)\\\\
-------------------------------\\\\\
%Simplify each expression. (1−cos⁡(−t))(1+cos⁡(t)) = (1+sin(t))(1+sin(-t))= csc⁡(t)tan⁡(t)+sec⁡(−t) =
[1+sin(t)][1+sin(-t)]\implies [1+sin(t)][1-sin(t)]
\\\\\\
1^2-sin^2(t)\implies 1-sin^2(t)\implies cos^2(t)\\\\
-------------------------------\\\\$

$\bf csc(t)tan(t)+sec(-t)\implies \cfrac{1}{\underline{sin(t)}}\cdot \cfrac{\underline{sin(t)}}{cos(t)}+\cfrac{1}{cos(-t)}
\\\\\\
\cfrac{1}{cos(t)}+\cfrac{1}{cos(-t)}\implies \cfrac{1}{cos(t)}+\cfrac{1}{cos(t)}\implies \cfrac{2}{cos(t)}
\\\\\\
2\cdot \cfrac{1}{cos(t)}\implies 2sec(t)$

3 0

3 years ago

A movie is 2 hours and 28 minutes long it starts at 7:50 a.m. at what time will the movie end

Marina CMI [18]

Answer:

10:18

Step-by-step explanation:

7:50+ 2=8:10

+8+8:18

2+8=10

10:18

8 0

2 years ago

Read 2 more answers

What is the answer to a+a-7=2a-8+1

igor_vitrenko [27]

The answer is 66 cause his hgivd jcunxf us to get the

3 0

3 years ago

g Given the following premises: (1) a∧(b∨a) (2) ~c→~a (3) ~g→~a (4) g→e (5)~(d∨h) Prove the Conclusion: c∧~h?

KIM [24]

Answer:

See the argument below

Step-by-step explanation:

I will give the argument in symbolic form, using rules of inference.

First, let's conclude c.

(1)⇒a by simplification of conjunction

a⇒¬(¬a) by double negation

¬(¬a)∧(2)⇒¬(¬c) by Modus tollens

¬(¬c)⇒c by double negation

Now, the premise (5) is equivalent to ¬d∧¬h which is one of De Morgan's laws. From simplification, we conclude ¬h. We also concluded c before, then by adjunction, we conclude c∧¬h.

An alternative approach to De Morgan's law is the following:

By contradiction proof, assume h is true.

h⇒d∨h by addition

(5)∧(d∨h)⇒¬(d∨h)∧(d∨h), a contradiction. Hence we conclude ¬h.

8 0

3 years ago

I Need help now!!!!

Kisachek [45]

Answer:

The answer is B.x2/4y3n hope it helps

6 0

2 years ago