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S_A_V [24]
2 years ago
11

Hey! please help i’ll give brainliest

Mathematics
2 answers:
madam [21]2 years ago
7 0

Answer:

Currently practice tennis

Step-by-step explanation:

The other options give either past tense or future tense, while the sentence is present tense.

Hope this helps :)

Rashid [163]2 years ago
5 0

Answer:D-Currently practice tennis

Step-by-step explanation:

I play tennis, PLAY is an action.

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Analyze the diagram below and complete the instructions that follow.
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I've looked at this over and over  the answer it's yes.

Step-by-step explanation:

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Rapid Rental Car charges a $45 rental fee, $15 for gas, and $0.75 per mile driven. For the same car, Capital
olga nikolaevna [1]

Your total cost will be 80

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2 years ago
Read 2 more answers
Abercrombie & Fitch is having a back-to-school sale
snow_lady [41]

Answer:

that normally cost $30 each. Including 6% sales tax,

what is the total Chaz pays?

Please answer very fast!

Abercrombie & Fitch is having a back-to-school sale

with all cargo shorts 30% off. Chaz buys 3 pairs of shorts

that normally cost $30 each. Including 6% sales tax,

what is the total Chaz pays?

Please answer very fast!

Step-by-step explanation:

Abercrombie & Fitch is having a back-to-school sale

with all cargo shorts 30% off. Chaz buys 3 pairs of shorts

that normally cost $30 each. Including 6% sales tax,

what is the total Chaz pays?

Please answer very fast!

6 0
2 years ago
Prove that the sum of the squares of the lengths of the medians of a triangle is three fourths the sum of the squares of the len
aleksandr82 [10.1K]

Answer:

3[|AB|² + |BC|² + |AC|²] = 4[|AD|² + |BE|² + |CF|²]

Step-by-step explanation:

I've attached an image showing a triangle divided into it's medians.

Now, from the attached image, we see that AB, BC & CD are the lengths of sides of triangle while AD, BE & CF are lengths of the 3 medians of the triangle.

Now, to prove our question, we will use appolonius theorem which states that "the sum of the squares of any of the two sides of a triangle is equal to twice the square on half the third side including twice the square on the median that bisects the third side.

Applying this theorem to the image attached, we have the following;

|AB|² + |AC|² = 2[|AD|² + |BC/2|²]

|AB|² + |BC|² = 2[|BE|² + |AC/2|²]

|AC|² + |BC|² = 2[|CF|² + |AB/2|²]

Adding the 3 equations above gives us;

2|AB|² + 2|BC|² + 2|AC|² = 2|AD|² + |BC|²/2 + 2|BE|² + |AC|²/2 + 2|CF|² + |AB|²/2

Collecting like terms;

(2|AB|² - |AB|²/2) + (2|BC|² - |BC|²/2) + (2|AC|² - |AC|²/2) = 2|AD|² + 2|BE|² + 2|CF|²

Thus gives;

(3/2)[|AB|² + |BC|² + |AC|²] = 2[|AD|² + |BE|² + |CF|²]

Multiply both sides by 2 to give;

3[|AB|² + |BC|² + |AC|²] = 4[|AD|² + |BE|² + |CF|²]

6 0
3 years ago
According to an advertisement for Colgate toothpaste, 4 out of 20 Dentist prefer Colgate. There are 150 Dentist in a certain cit
melamori03 [73]

Answer:

According to an advertisement for Colgate toothpaste, 4 out of 20 Dentist prefer Colgate. There are 150 Dentist in a certain city.

Let the number of dentists prefer Colgate in the city be x

\frac{4}{20}  =  \frac{x}{150}  \\ x =  \frac{4 \times 150}{20}  \\  \boxed{x = 30}

<h3>30 dentists prefer Colgate.</h3>

6 0
3 years ago
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