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2 years ago

Exercise No. 1

Mathematics

1 answer:

Leya [2.2K]2 years ago

8 0

Answer:

don't get it I don't know how to do it

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Researchers are studying the distribution of subscribers to a certain streaming service in different populations. From a random

Katen [24]

Answer:

$CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}$

Step-by-step explanation:

Given

$n = 200$

$x_1 = 34$ -- City C

$x_2 = 54$ --- City K

Required

Determine the 90% confidence interval

This is calculated using:

$CI = \bar x \± z\frac{\sigma}{\sqrt n}$

Calculating $\bar x$

$\bar x = \bar x_1 - \bar x_2$

$\bar x = \frac{x_1}{n} - \frac{x_2}{n}$

$\bar x = \frac{34}{200} - \frac{54}{200}$

$\bar x = 0.17 - 0.27$

For a 90% confidence level, the z-score is 1.65. So:

$z = 1.65$

Calculating the standard deviation $\sigma$

$\sigma = \sqrt{(\bar x_1)*(1 - \bar x_1) + (\bar x_2)*(1 - \bar x_2) }$

So:

$\sigma = \sqrt{(0.17)*(1 - 0.17) + (0.27)*(1 - 0.27) }$

$\sigma = \sqrt{(0.17)*(0.83) + (0.27)*(0.73)}$

So:

$CI = (0.17 - 0.27)\± 1.65\frac{\sqrt{(0.17)*(0.83) + (0.27)*(0.73)}}{\sqrt {200}}$

$CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}$

7 0

2 years ago

Which triangles can have two sides of the same lenghth

alisha [4.7K]

An isosceles triangle is a triangle with 2 congruent sides. The congruent sides are called legs and the third side is called the base. So if 2 sides of a triangle have the same length, then we say that the triangle is isosceles.

8 0

2 years ago

Help please <br> Help please

love history [14]

Answer:

1. 1,605

2. -605

3. 21,575

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

A pill has the shape of a cylinder with a hemisphere at each end. The height of the cylindrical portion is 12mm and the overall

Volgvan

Answer:

The volume of the pill is $V=452\ mm^{3}$

Step-by-step explanation:

Find the volume of the pill in cubic millimeters

we know that

The volume of the pill is equal to the volume of the cylinder plus the volume of a sphere (two hemisphere is equal to one sphere)

we have

$V=\frac{4}{3}\pi r^{3}+\pi r^{2}h$

$r= (18-12)/2=3\ mm\\ h=12\ mm$

assume

$\pi =3.14$

substitute

$V=\frac{4}{3}(3.14)(3)^{3}+(3.14)(3)^{2}(12)\\V=452\ mm^{3}$

8 0

3 years ago

Can you please give the answer for this problem? :<br> 18+11v=w-13t for t

Kay [80]

18+11v=w-13t
18+11-w=-13t
13t=w-11v-18
t=1/13w - 11/13v - 1 5/13

Hope this helps :)

6 0

2 years ago