Exercise No. 1
1 answer:
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Answer:
The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
Of the 2809 people who responded to survey, 1634 stated that they currently use social media.
This means that
98% confidence level
So , z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:
The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).
Answer:
Step-by-step explanation:
The missing image is attached below.
From the given information
The number of players is 44.
From the box plot;
The minimum weight = 154 pounds
The first quartile Q₁ = 159 which is 25% of the data below 159 pounds.
The second quartile Q₂ = 213 which is 50% of the data below 213 pounds
The third quartile Q₃ = 253 which is 75% of the data below 253 pounds
The maximum weight = 268 pounds.
Here, the value of 213 is the middle value and which signifies the median.
The 50% of the data are located both on the left side and the right side of the median.
Thus, the percentage of players weighting greater than or equal to 213 pounds is 50%.
