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Anastaziya [24]
3 years ago
11

PLEASEE HELP.!! ILL GIVE BRAINLIEST.!! *EXTRA POINTS* DONT SKIP:((

Mathematics
2 answers:
nalin [4]3 years ago
7 0

Answer:

-12

Step-by-step explanation:

Its -12 for sure!!!!!

zhannawk [14.2K]3 years ago
6 0

Answer:

-12

Step-by-step explanation:

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someone please do this for me... i will mark brainliest. all work needs to be shown. (picture shown above)
ivolga24 [154]

Step-by-step explanation:

just use step by step process so dum

6 0
3 years ago
Among all pairs of numbers (x,y) such that 3x+y=15, find the pair for which the sum of squares, x^2+y^2, is minimum. Write your
Dvinal [7]

Answer:

Minimum value occurs at (x, y) = (-5,0)

Step-by-step explanation:

Given: 3x + y =15

Rewriting this equation to Slope - Intercept form, we get:

y = -3x + 15

Squaring both sides,

$ y^2 = (-3x + 15)^2 $

$ \implies y^2 = 9x^2 - 90x + 225 $

Substituting in $ x^2 + y^2,$ we get:

$ x^2 + 9x^2 - 90x + 225 $

= $ 10x^2 - 90x + 225 $

Comparing this equation with $ ax^2 + bx + c $ we get $ a =10 $ and $ b = - 90 $.

The minimum value occurs at the axis of symmetry given by $ x = \frac{-b}{2a} $.

Therefore, x = - $ \frac{-90}{2.10} $

$ \implies x = 5 $

If x = 5, y = -3(5) + 15 = 0

Thus, the point becomes (5,0) where it is minimum.

5 0
4 years ago
An envelope with 96 bookmarks in it has a mass of 1467 grams. The same envelope with 49 bookmarks in it has a mass of 762 grams.
masya89 [10]

If m is the mass of the envelope and b the mass of one bookmark, then

\begin{cases}m+96b=1467\\m+49b=762\end{cases}

We have

(m+96b)-(m+49b)=1467-762\implies47b=705\implies b=15

Then

m+96\cdot15=1467\implies m+1440=1467\implies m=27

so the envelope has a mass of 27 grams.

8 0
4 years ago
Can you please venmo me $5​
Westkost [7]

Answer:

no sorry dude :/

3 0
3 years ago
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The equation for momentum is p = mv where p is the momentum, m is the mass and v is the velocity. Calculating the momentum for each football player, player A will have a momentum of 1050 lb-mi/h and player B will have a momentum of 570 lb-mi/h. Therefore, momentum of player A is greater than that of player B.

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3 years ago
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