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Anastaziya [24]
3 years ago
11

PLEASEE HELP.!! ILL GIVE BRAINLIEST.!! *EXTRA POINTS* DONT SKIP:((

Mathematics
2 answers:
nalin [4]3 years ago
7 0

Answer:

-12

Step-by-step explanation:

Its -12 for sure!!!!!

zhannawk [14.2K]3 years ago
6 0

Answer:

-12

Step-by-step explanation:

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Carlos tiene 3 chocolates más que mariana, mariana tiene 3 chocolates más que verónica y verónica tiene 3 chocolates más que lui
Elden [556K]
Carlos : 23.5


Mariana : 20.5


Verónica : 17.5


Luis : 14.5





I THINK !!!
I DONT KNOW IF IM RIGHT!!!!!


6 0
3 years ago
How many solutions are there to the equation below? 4(x-5)=4x-24
blondinia [14]

It is a linear equation so there can be 1 solution, 0 solutions, or infinite solutions

4(x-5)=4x-24

distribute

4x -20 = 4x-24

subtract 4x from each side

-20 = -24

no solutions


6 0
3 years ago
Read 2 more answers
eight wooden spheres with radii 3 in. are packed snugly into a square box 12 in. on one side. the remaining space is filled with
ZanzabumX [31]
Vbox-vspheres

vbox=, I assume we are dealing with l=w=h
so
v=lwh=12^3=1728

vsphere=(4/3)pir^3
r=3
vsphere=(4/3)pi3^3=4pi9=36pi
8 of them so
8 times 36pi=288pi or about 904.7786842338604526772412943845 cubic inches



vbox-sphere=1728-904.7786842338604526772412943845=823.2213157661395473227587056155
space filled by packing beads is about 823.22 cubic inches
beads percent is 823.2213157661395473227587056155/1728 times 100=47.64% filled by beads






3 0
3 years ago
The system of equations Y =-3x+2 and Y = 3x-6 is shown on the graph below.
Ira Lisetskai [31]

Answer:

A

Step-by-step explanation:

8 0
3 years ago
Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega
AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

To find the simplified form of the given expression :

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2 ( using the property (ab)^m=a^m.b^m )

=(2^6)(3^{-12})\times (2^{-6})(3^4) ( using the property (a^m)^n=a^{mn}

=(2^6)(2^{-6})(3^{-12})(3^4) ( combining the like powers )

=2^{6-6}3^{-12+4} ( using the property a^m.a^n=a^{m+n} )

=2^03^{-8}

=\frac{1}{3^8} ( using the property a^{-m}=\frac{1}{a^m} )

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

6 0
4 years ago
Read 2 more answers
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