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2 years ago

11. For each table Ariella waits on at a restaurant, she is paid $4.00 plus 18% of the

Mathematics

1 answer:

lisabon 2012 [21]2 years ago

5 0

Answer:

m=0.18b+4

She'll earn $10.30

Step-by-step explanation:

m=0.18b+4

m=0.18(35)+4

m=6.3+4

m=10.3

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Which of the following functions is graphed above?

denis-greek [22]

Answer:

i'm pretty sure it is c

Step-by-step explanation:

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3 years ago

Read 2 more answers

A construction company is considering submitting bids for contracts of three different projects. The company estimates that it h

julsineya [31]

Answer:

a. $P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\$

b. $E(x) = 0.3$

c. $S(x)=0.5196$

d. $E=5,000$

Step-by-step explanation:

The probability that the company won x bids follows a binomial distribution because we have n identical and independent experiments with a probability p of success and (1-p) of fail.

So, the PMF of X is equal to:

$P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\$

Where p is 0.1 and it is the chance of winning. Additionally, n is 3 and it is the number of bids. So the PMF of X is:

$P(x)=\frac{3!}{x!(3-x)!}*0.1^{x}*(1-0.1)^{n-x}\\$

For binomial distribution:

$E(x)=np\\S(x)=\sqrt{np(1-p)}$

Therefore, the company can expect to win 0.3 bids and it is calculated as:

$E(x) = np = 3*0.1 = 0.3$

Additionally, the standard deviation of the number of bids won is:

$S(x)=\sqrt{np(1-p)}=\sqrt{3(0.1)(1-0.1)}=0.5196$

Finally, the probability to won 1, 2 or 3 bids is equal to:

$P(1)=\frac{3!}{1!(3-1)!}*0.1^{1}*(1-0.1)^{3-1}=0.243\\P(2)=\frac{3!}{2!(3-2)!}*0.1^{2}*(1-0.1)^{3-2}=0.027\\P(3)=\frac{3!}{3!(3-3)!}*0.1^{3}*(1-0.1)^{3-3}=0.001$

So, the expected profit for the company is equal to:

$E=-10,000+50,000(0.243)+100,000(0.027)+150,000(0.001)\\E=5,000$

Because there is a probability of 0.243 to win one bid and it will produce 50,000 of income, there is a probability of 0.027 to win 2 bids and it will produce 100,000 of income and there is a probability of 0.001 to win 3 bids and it will produce 150,000 of income.

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3 years ago

Randomization in an experiment is important because it ensures that

Alexeev081 [22]

Answer:

C.) each treatment is thought of as a value of the explanatory variable

Step-by-step explanation:

The main purpose for using randomization in an experiment is to control the lurking variable and establish a cause and effect relationship.

If we do not control lurking, or confounding, variables, we cannot accurately establish a cause and effect relationship; this means we cannot ensure that each treatment is a value of the explanatory variable.

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2 years ago

I need help with solving it

mars1129 [50]

The given equation has a slope of $\frac{-9}{7}$ . Parallel lines have the same slope.