Answer:
Real values of x where x < -1
Step-by-step explanation:
Above the x-axis, the function is positive.
The function is decreasing when the gradient is negative.
The function has a positive
coefficient, therefore the vertex is a local minimum;
This means the gradients are negative before the vertex and positive after it;
To meet the conditions therefore, the function must be before the vertex and above the x-axis;
This will be anywhere before the x-intercept at x = -1;
Hence it is when x < -1.
Answer:
Step-by-step explanation:
Equation of a line is given as 
Where,
m = slope of the line = 
b = y-intercept, which is the value at the point where the line intercepts the y-axis. At this point, x = 0.
Let's find m and b to derive the equation for the line.
Use the coordinate pair of any two points on the line. Let's use the following,
=> on the line, when x = 0, y = -2
=> on the line, when x = 4, y = 1
Plug in the values and solve for m
b = -2 (the line intercepts the y-axis at this point)
Our equation would be =>
Slope is the change in Y over the change in X:
Slope = (6 - -8) / (5 - -3)
Slope = (6+8) / (5+3)
Slope = 14/8
Slope = 7/4
N/d = 2/3 -------------------> 3n = 2d
(n + 2)/(d + 2) = 3/4 ------> 4n + 8 = 3d + 6
