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Mariulka [41]
2 years ago
8

A football team has a net yardage of -33 - yards on a series of plays. The team needs a net yardage of 10

Mathematics
1 answer:
sukhopar [10]2 years ago
4 0

Answer: Assuming that it's 4th down the team would need 43 yards to get a net yardage of 10

Step-by-step explanation:

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A teacher has a box of pens and pencils. There are 8 more pencils than pens. After the students take 1 pen and 5 pencils from th
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Let no. of pens be x.

Pens : x
Pencils: x+8

Total: 2x+8

Student takes 1 pen and 5 pencils.

Remainder: 2x+8 - 5 -1 = 2x+2
2x+2 = 26
2x= 24
x = 12 (original no. of pens)
x+ 8 = 20 (original no of pencils)

There are 12 pens at first and 20 pencils.
After 1 pen is taken, 11 pens are left.
After 5 pencils are taken, 20-5=15 pencils are left.
5 0
3 years ago
Read 2 more answers
Dwayne's garden is triangle-shaped with two equal sides and a third side that is 4 ft more than the length of an equal side. The
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D because its a triangle so it would be 3x but then you have to add the 4 for the longer side.

8 0
3 years ago
Vivenne, John and nassim ran for 6th grade class president. Vivenne got four votes for every 3 votes that John got. Nassim got t
liq [111]

Answer:

John received 10% of the overall votes.

Step-by-step explanation:

Let us assume that the number of votes John got  = m

So, the number of votes Vivienne received =   3 times (John's share )

 = 3  times m   =  3 m

Also, The number of Votes Nassim received = 2 times ( Vivienne's share)

2 x (3 m)   = 6 m

Total Votes in the grade 6  

= Votes received by { John + Vivienne + Nassim}

= m + (3 m) + (6 m) = 10 m

Hence, the total number of students who voted in grade 6  = 10 m

\textrm{The percentage of John's Votes }  = \frac{\textrm{Number of votes John received}}{\textrm{Total number of votes }}  \times 100

= \frac{m}{10m}  \times 100 = 10

or, The percentage of John's Votes  = 10%

Hence, John received 10% of the overall votes.

3 0
3 years ago
Can anybody answer this correctly thank you
Ghella [55]

its the second one....

4 0
3 years ago
Strong positive<br> strong negative<br> weak positive<br> weak negative
Nesterboy [21]
If you're looking for the trend name, I would say Strong Positive, or (a).


6 0
2 years ago
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