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3 years ago

What is the intersection of the given lines? CD MD

Mathematics

1 answer:

kati45 [8]3 years ago

5 0

Point D is obviously on both lines.

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7. How many runners' times are

Sophie [7]

Answer:

314

Step-by-step explanation:

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3 years ago

What is:<br> -6s²+-4.5=?

ddd [48]

Answer:

-6s² + - 4.5

= -6s² +(-4.5)

= -6s² - 4.5

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3 years ago

Read 2 more answers

The figure shows a swing blown to one side by a

wariber [46]

Answer:

AB=2 ft

ED=4.5 ft

BD=9 ft

m∠ABC=105°

m∠BCD=105°

m∠ADC=75°

Step-by-step explanation:

4 0

3 years ago

On 1<br> -4 is to the left of O so that means O is<br> than -4. Greater Less

tiny-mole [99]

Answer:

O is greater than -4

Step-by-step explanation:

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3 years ago

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a rectangular dog kennel is to be constructed alongside a house with 60m of fencing. If the house serves as one side of the kenn

Basile [38]

Answer:

$450\text{ m}^2$ .

Step-by-step explanation:

Let x represent side of kennel opposite to house and y represent other sides.

We have been given that a rectangular dog kennel is to be constructed alongside a house with 60 m of fencing.

Since fencing will cover 3 sides of kennel, so perimeter of kennel would be:

$x+y+y=60$

$x+2y=60$

Let us solve for x.

$x+2y-2y=60-2y$

$x=60-2y$

The area of the kennel would be product of its sides that is:

$\text{Area}=x\cdot y$

Now, we will substitute $x=60-2y$ in area equation as:

$A(y)=(60-2y)\cdot y$

$A(y)=60y-2y^2$

Let us find the derivative as shown below:

$A'(y)=60-4y$

Now, we will set derivative equal to 0 and solve for y.

$60-4y=0$

$60=4y$

$\frac{60}{4}=\frac{4y}{4}$

$y=15$

Upon substituting $y=15$ in area function, we will greatest possible area.

$A(y)=60y-2y^2$

$A(15)=60(15)-2(15)^2$

$A(15)=900-2(225)$

$A(15)=900-450$

$A(y)=450$

Therefore, the greatest possible area that can be enclosed by 60 m of fencing is 450 square meters.

5 0

3 years ago