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3 years ago

Hey people! Guess what? I need help :D Attached is a picture that has the problem please explain how you did it!

Mathematics

2 answers:

Leviafan [203]3 years ago

8 0

The answer is 1.07 :)

damaskus [11]3 years ago

7 0

Answer:

1.07

Step-by-step explanation:

because 13 divided by 13.91 is 1.07

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Seven more than three times a number is twenty-eight.

m_a_m_a [10]

Answer:

7+3n=28 and the answer would be n=7

Step-by-step explanation:

7+3n=28 subtract 7 on both sides, that would leave 3n=21, divide 3 on both sides, the answer would be n=7 if I'm correct. I hope I helped.

7 0

2 years ago

F(x) = 4/x-9 g(x)=4/x + 9 find f(g(x))

Alenkinab [10]

Hello,

$f(x)= \dfrac{4}{x-9} \\

g(x)= \dfrac{4}{x+9} \\

f(g(x))=f( \dfrac{4}{x+9} )\\

= \dfrac{4}{ \dfrac{4}{x+9}-9} \\

= \dfrac{4(x+9)}{4-9x-81} \\

=- \dfrac{4x+36}{77x+9x} 


$

6 0

3 years ago

Convert a distance of 42 feet into yards.

dybincka [34]

Answer:

14 Yards

Step-by-step explanation:

8 0

3 years ago

A box with a hinged lid is to be made out of a rectangular piece of cardboard that measures 3 centimeters by 5 centimeters. Six

kherson [118]

Answer:

x = 0.53 cm

Maximum volume = 1.75 cm³

Step-by-step explanation:

Refer to the attached diagram:

The volume of the box is given by

$V = Length \times Width \times Height \\\\$

Let x denote the length of the sides of the square as shown in the diagram.

The width of the shaded region is given by

$Width = 3 - 2x \\\\$

The length of the shaded region is given by

$Length = \frac{1}{2} (5 - 3x) \\\\$

So, the volume of the box becomes,

$V = \frac{1}{2} (5 - 3x) \times (3 - 2x) \times x \\\\V = \frac{1}{2} (5 - 3x) \times (3x - 2x^2) \\\\V = \frac{1}{2} (15x -10x^2 -9 x^2 + 6 x^3) \\\\V = \frac{1}{2} (6x^3 -19x^2 + 15x) \\\\$

In order to maximize the volume enclosed by the box, take the derivative of volume and set it to zero.

$\frac{dV}{dx} = 0 \\\\\frac{dV}{dx} = \frac{d}{dx} ( \frac{1}{2} (6x^3 -19x^2 + 15x)) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\0 = \frac{1}{2} (18x^2 -38x + 15) \\\\18x^2 -38x + 15 = 0 \\\\$

We are left with a quadratic equation.

We may solve the quadratic equation using quadratic formula.

The quadratic formula is given by

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Where

$a = 18 \\\\b = -38 \\\\c = 15 \\\\$

$x=\frac{-(-38)\pm\sqrt{(-38)^2-4(18)(15)}}{2(18)} \\\\x=\frac{38\pm\sqrt{(1444- 1080}}{36} \\\\x=\frac{38\pm\sqrt{(364}}{36} \\\\x=\frac{38\pm 19.078}{36} \\\\x=\frac{38 + 19.078}{36} \: or \: x=\frac{38 - 19.078}{36}\\\\x= 1.59 \: or \: x = 0.53 \\\\$