Hey people! Guess what? I need help :D Attached is a picture that has the problem please explain how you did it!
2 answers:
You might be interested in
Answer:
1. (7.4,3.6)
2. (3,-1)
3. (-2,-3)
4. Infinite number of solutions.
Step-by-step explanation:
We can solve systems of equations 3 ways: graphing, substitution, and elimination. We will solve 1-2, 4 using substitution and 3 with elimination.
1. Since x=4y-7, we substitute it in for x . It's better than elimination because of how it is set-up unless there is a typo.
- So -4x+4y=-8 becomes -4(4y-7)+4y=-8.
- We simplify to -14y+28+4y=-8.
- We add like terms to get -10y+28=-8.
- We now solve for y by subtracting 28 and dividing by -10.
- -10y+28-28=-8-28
- -10y=-36
- y=3.6
- We substitute y=3.6 into x=4y-7. x=4(3.6)-7=14.4-7=7.4
2. Since none of the coefficients of x & y are the same, we will rearrange and substitute.
- -8x+2y=-26 becomes 2y=8x-26 by adding 8x to both side.
- We divide by 2. y=4x-13.
- We substitute into -5x-5y=-10. -5x-5(4x-13)=-10
- We simplify to -5x-20x+65=-10
- We add like terms. -25x+65=-10
- We now solve for x by subtracting 65 and dividing by -25.
- -25x+65-65=-10-65
- -25x=-75
- x=3
- We substitute x=3 into -8(3)+2y=-26
- -24+2y=-26
- 2y=-2
- y=-1
3. We can solve this system through elimination. We subtract or add the equations when the coefficients are the same to eliminate one variable.
- We susbstitute y=-3 into one of the equations 3x-(-3)=-3.
- 3x=-6
- x=-2
4. Since none of the coefficients of x & y are the same, we will rearrange and substitute.
- -x+y=-2 becomes y=x-2
- We substitute into 4x-4(x-2)=8.
- Simplify 4x-4x+8=8.
- Add like terms 0x+8=8
- 8=8
- This is a true statement and a special solution. It means infinite number of solutions.
Answer:
He traveled at 72km/hr during the rain
Step-by-step explanation:
<em>Question is not well formatted. See comment</em>
Given
--- distance
--- total time
Let his speed from city A till the rain starts on his return trip be
Let his speed from city during the rain be
So:
Required
Calculate
From the question, we understand that; he drives the whole 400 km and 2/5 of 400 km at
The distance covered during this period is:
And the time during this period is:
So, the distance during the rain is:
And the time during the rain is:
So, we have:
--- distance covered before the rain
--- distance covered when raining
---- time spent before the rain
--- time spent in the rain
Speed is calculated as:
Make distance the subject
So:
Recall that:
Make the subject
The expression becomes:
Collect like terms
Solve for