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bekas [8.4K]
2 years ago
13

Hey people! Guess what? I need help :D Attached is a picture that has the problem please explain how you did it!

Mathematics
2 answers:
Leviafan [203]2 years ago
8 0
The answer is 1.07 :)
damaskus [11]2 years ago
7 0

Answer:

1.07  

Step-by-step explanation:

because 13 divided by 13.91 is 1.07

You might be interested in
PLEASE FOLLOW THE DIRECTIONS AND SHOW YOUR WORK. IM OFFERING 15PTS (Way more than its worth) AND BRAINLIEST ANSWER. PLEASE HELP
Alex
I'll take this challenge since I'm not feeling lazy for once....   x would represent Gavin and y would represent Seiji.  

a.  x+y=425, x-y=25   




b.   I will solve your system using substitution.    
x+y-425, x-y=25  
<span>Step 1: Solve </span>x+y=425 for x
x+y+-y=425+-y (add -y for both sides)
x=-y+425
<span>Step 2: substitute </span>-y+425 for x in x+b=25
x+y=25
<span></span>-y+425-y=25
-2y+425=25 (simplify both sides of the equation)
-2y+425+-425=25+-425 (add -425 to both sides)<span>
</span> -2y=-400
\frac{-2y}{-2} =  \frac{-400}{-2}
y=200
step 3: substitute 200 for y in x=-y+425
x=-y+425
x=-200+425&#10;
x=225
x=225, y= 200




c.   Already answered with the picture that is attached.



d.   Gavin earned 225 dollars while Seiji earned 200 dollars.  

3 0
3 years ago
If vectors u,v and w ar linearly indepndnt, will u-v,v-w &amp; u-w also be linearly indpnt? ...?
inna [77]
No they won’t be.Consider the linear combination (1)(u – v) + (1) (v – w) + (-1)(u – w).This will add to 0. But the coefficients aren’t all 0.Therefore, those vectors aren’t linearly independent.
You can try an example of this with (1, 0, 0), (0, 1, 0), and (0, 0, 1), the usual basis vectors of R3.
That method relied on spotting the solution immediately.If you couldn’t see that, then there’s another approach to the problem.
We know that u, v, w are linearly independent vectors.So if au + bv + cw = 0, then a, b, and c are all 0 by definition.
Suppose we wanted to ask whether u – v, v – w, and u – w are linearly independent.Then we’d like to see if there are non-zero coefficients in the linear combinationd(u – v) + e(v – w) + f(u – w) = 0, where d, e, and f are scalars.
Distributing, we get du – dv + ev – ew + fu – fw = 0.Then regrouping by vector: (d + f)u + (-d +e)v + (-e – f)w = 0.
But now we have a linear combo of u, v, and w vectors.Therefore, all the coefficients must be 0.So d + f = 0, -d + e = 0, and –e – f = 0. It turns out that there’s a free variable in this solution.Say you let d be the free variable.Then we see f = -d and e = d.
Then any solution of the form (d, e, f) = (d, d, -d) will make (d + f)u + (-d +e)v + (-e – f)w = 0 a true statement.
Let d = 1 and you get our original solution. You can let d = 2, 3, or anything if you want.

6 0
3 years ago
) If the gradient of ff is ∇f=xi⃗ +yj⃗ +3zyk⃗ ∇f=xi→+yj→+3zyk→ and the point P=(−6,−6,−2)P=(−6,−6,−2) lies on the level surface
Paha777 [63]

Answer:

-3x-3y-z=38

Step-by-step explanation:

To find the equation of the tangent plane you can use

\bigtriangledown f_x(x_0,y_0,z_0)(x-x_0)+\bigtriangledown f_y(x_0,y_0,z_0)(y-y_0)+\bigtriangledown f_z(x_0,y_0,z_0)(z-z_0)=0

the point P is (-6,-6,-2). Hence you have

(-6)(x-(-6))+(-6)(y-(-6))+(-2)(z-(-2))=0\\-6x-36-6y-36-2z-4=0\\-6x-6y-2z=76\\-3x-3y-z=38

hope this helps!!

5 0
3 years ago
PLS HELP I HAVE TO DO THIS BY TONIGHTT
gtnhenbr [62]

I got you !

Step-by-step explanation:

45 bulbs planted in first year.

65 bulbs the next year.

increase = 20 bulbs

Number of increase of planted tulip bulb is N = 65 - 45 = 20

( 20/45)  x 100% = 44.4 % to the nearest tenths

3 0
2 years ago
Amy scores 7760 points on a new game, to the nearest 10.
KonstantinChe [14]

Answer:Bill

Step-by-step explanation:

Because Bill scored to the nearest 100

7 0
2 years ago
Read 2 more answers
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