The answer is C.
Starting from the bottom point, you go up 7 and go to the right 2, which makes the slop 7/2
Depth of the well=30 feet
length the snail ascends during day = 3 feet
length it descends at night = 2 feet
therefore, the equivalent length it covers at the end of the day=(3-2)feet = 1 feet
So, After 27 days it will cover: 27 feet
Then, the next day it will cover : (27+3) feet = 30 feet
Therefore, the snail takes (27+1)days i.e. 28 days to climb out of the well.......
Answer:
The data that we have is:
"Adrian's backyard pool contains 6.4 gallons of water. Adrian will begin filling his pool at a rate of 4.1 gallons per second."
Then we can write the amount of water in Adrian's pool as a linear function:
A(t) = 6.4gal + (4.1gal/s)*t
Where t is our variable and represents time in seconds.
We also know that:
"Dale's backyard pool contains 66.4 gallons of water. Dale will begin draining his pool at a rate of 0.9 gallons per second. "
We can also model this with a linear function:
D(t) = 66.4 gal + (0.9gal/s)*t
Both pools will have the same amount of water when:
D(t) = A(t)
So we can find the value of t:
6.4gal + (4.1gal/s)*t = 66.4 gal + (0.9gal/s)*t
(4.1gal/s)*t - (0.9gal/s)*t = 66.4gal - 6.4gal
(3.2gal/s)*t = 60gal
t = 60gal/(3.2gal/s) = 18.75s
In 18.75 seconds both pools will have the same amount of water.
Answer:
606.25
Step-by-step explanation:
Step 1: D for Divide. How many times will 5 go into 65? ...
Step 2: M for Multiply. You multiply your answer from step 1 and your divisor: 1 x 5 = 5. ...
Step 3: S for Subtract. Next you subtract. ...
Step 4: B for Bring down. ...
Step 1: D for Divide. ...
Step 2: M for Multiply. ...
Step 3: S for Subtract.
1) 4c*2
2)a*2
3)c
.........................*=square
