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natita [175]
3 years ago
12

For the past year, Kayla, Inc., has sales of $46,382, interest expense of $3,854, cost of goods sold of $16,659, selling and adm

inistrative expense of $11,766, and depreciation of $6,415. If the tax rate is 35 percent, what is the operating cash flow
Business
1 answer:
grandymaker [24]3 years ago
3 0

Answer:

$15,266

Explanation:

Sales                                                          $46,382

Less: Cost of goods sold                          <u>$16,659</u>

Gross profit                                                $29,723

Less: Selling & administrative expense   $11,766

Less: Depreciation                                     <u>$6,415</u>

Earnings before interest and tax (EBIT)    $11,542

Less: Interest expenses                             <u>$3,854</u>

Earnings before tax (EBT)                           $7,688

Less: Tax expenses  (7688*35%)               <u>$2,691</u>

Earnings after tax                                       <u>$4,997</u>

Operating cash flow = EBIT + Depreciation expenses - Tax expenses

Operating cash flow = $11,542 + $6,415 - $2,691

Operating cash flow = $15,266

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The correct answer is letter "D": brand equity.

Explanation:

Brand equity is the value a company gains from its name recognition. To ensure customer loyalty the brand equity so valuable, companies must consistently produce quality products. This creates loyal customers who are willing to pay more for a preferred brand.

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Which of the following is not a type of business organization
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A charity, for exampl,e is not a business organizaaation.
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Read 2 more answers
The Herman Company uses a joint process to produce products W, X, Y and Z. Each product may be sold at its split-off point or pr
Gala2k [10]

Answer:

<em>W:</em> positive contribution of 6,000

<em>Z:</em>  positive contribution of 1,000

<em>X:</em> negative of 1,000

<em>Y:</em> negative of 6,500

Explanation:

value at the end- value at split off  = value added for processing:

value added - addtional cost = advantage/disadvantage of processing

W (22,500- 7,500) - 9,000  = 15,000 - 9,000 = 6,000

X (20,000 - 13,5000) - 7,500 = 6,500 - 7,500 = (1,000)

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Z (12,500 - 6,500) - 5,500 = 6,000 - 5,500 = 1,000

7 0
3 years ago
Jeff is an entrepreneur who decided to start an online bakery. Since all his business will be done online and he can bake in his
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Answer:

competition                  

Explanation:      

In simple words, competition refers to the tendency of two or more parties to perform better than one another for the sake of own personal benefits. In business, competition can be done from various perspectives like price or quality.

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3 years ago
Suppose that output (Y ) in an economy is given by the following aggregate production function: Yt = Kt + Nt where Kt is capital
shusha [124]

Answer:

Check the explanation

Explanation:

Yt = Kt + Nt

Taking output per worker, we divide by Nt

Yt/Nt = Kt/Nt + 1

yt = kt + 1

where yt is output per worker and kt is capital per worker.

a) With population being constant, savings rate s and depreciation rate δ.

ΔKt = It - δKt

dividing by Nt, we get

ΔKt/Nt = It/Nt - δKt/Nt ..... [1]

for kt = Kt/Nt, taking derivative

d(kt)/dt = d(Kt/Nt)/dt ... since Nt is a constant, we have

d(kt)/dt = d(Kt/Nt)/dt = (dKt/dt)/Nt = ΔKt/Nt = It/Nt - δKt/Nt = it - δkt

thus, Capital accumulation Δkt = i – δkt

In steady state, Δkt = 0

That is I – δkt = 0

S = I means that I = s.yt

Thus, s.yt – δkt = 0

Then kt* = s/δ(yt) = s(kt+1)/(δ )

kt*= skt/(δ) + s/(δ)

kt* - skt*/(δ) = s/(δ)

kt*(1- s/(δ) = s/(δ)

kt*((δ - s)/(δ) = s/(δ)

kt*(δ-s)) = s

kt* = s/(δ -s)

capital per worker is given by kt*

b) with population growth rate of n,

d(kt)/dt = d(Kt/Nt)/dt =

= \frac{\frac{dKt}{dt}Nt - \frac{dNt}{dt}Kt}{N^{2}t}

= \frac{dKt/dt}{Nt} - \frac{dNt/dt}{Nt}.\frac{Kt}{Nt}

= ΔKt/Nt - n.kt

because (dNt/dt)/Nt = growth rate of population = n and Kt/Nt = kt (capital per worker)

so, d(kt)/dt = ΔKt/Nt - n.kt

Δkt = ΔKt/Nt - n.kt = It/Nt - δKt/Nt - n.kt ......(from [1])

Δkt = it - δkt - n.kt

at steady state Δkt = it - δkt - n.kt = 0

s.yt - (δ + n)kt = 0........... since it = s.yt

kt* = s.yt/(δ + n) =s(kt+1)/(δ + n)

kt*= skt/(δ + n) + s/(δ + n)

kt* - skt*/(δ + n) = s/(δ + n)

kt*(1- s/(δ + n)) = s/(δ + n)

kt*((δ + n - s)/(δ + n)) = s/(δ + n)

kt*(δ + n -s)) = s

kt* = s/(δ + n -s)

.... is the steady state level of capital per worker with population growth rate of n.

3. a) capital per worker. in steady state Δkt = 0 therefore, growth rate of kt is zero

b) output per worker, yt = kt + 1

g(yt) = g(kt) = 0

since capital per worker is not growing, output per worker also does not grow.

c)capital.

kt* = s/(δ + n -s)

Kt*/Nt = s/(δ + n -s)

Kt* = sNt/(δ + n -s)

taking derivative with respect to t.

d(Kt*)/dt = s/(δ + n -s). dNt/dt

(dNt/dt)/N =n (population growth rate)

so dNt/dt = n.Nt

d(Kt*)/dt = s/(δ + n -s).n.Nt

dividing by Kt*

(d(Kt*)/dt)/Kt* = s/(δ + n -s).n.Nt/Kt* = sn/(δ + n -s). (Nt/Kt)

\frac{sn}{\delta +n-s}.\frac{Nt}{Kt}

using K/N = k

\frac{s}{\delta +n-s}.\frac{n}{kt}

plugging the value of kt*

\frac{sn}{\delta +n-s}.\frac{(\delta + n -s)}{s}

n

thus, Capital K grows at rate n

d) Yt = Kt + Nt

dYt/dt = dKt/dt + dNt/dt = s/(δ + n -s).n.Nt + n.Nt

using d(Kt*)/dt = s/(δ + n -s).n.Nt from previous part and that (dNt/dt)/N =n

dYt/dt = n.Nt(s/(δ + n -s) + 1) = n.Nt(s+ δ + n -s)/(δ + n -s) = n.Nt((δ + n)/(δ + n -s)

dYt/dt = n.Nt((δ + n)/(δ + n -s)

dividing by Yt

g(Yt) = n.(δ + n)/(δ + n -s).Nt/Yt

since Yt/Nt = yt

g(Yt) = n.(δ + n)/(δ + n -s) (1/yt)

at kt* = s/(δ + n -s), yt* = kt* + 1

so yt* = s/(δ + n -s) + 1 = (s + δ + n -s)/(δ + n -s) = (δ + n)/(δ + n -s)

thus, g(Yt) = n.(δ + n)/(δ + n -s) (1/yt) =  n.(δ + n)/(δ + n -s) ((δ + n -s)/(δ + n)) = n

therefore, in steady state Yt grows at rate n.

5 0
3 years ago
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