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kari74 [83]
3 years ago
12

Efectuati calculele:

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
8 0
\sqrt{(5 - 1)^{2}} +  \sqrt{20}

\sqrt{4^{2}} +  \sqrt{4 * 5}

\sqrt{16} +  \sqrt{4} \sqrt{5} 


4 + 2 \sqrt{5} 


4\sqrt{5} + 2 \sqrt{5} 


6 \sqrt{5}


\sqrt{(10 - 3)^{2}} +  \sqrt{20 * 18}

\sqrt{7^{2}}  +  \sqrt{4 * 9 * 5 * 2}

\sqrt{49} +  \sqrt{36 * 10}

7 +  \sqrt{36}\sqrt{10}

7 + 6\sqrt{10}

7\sqrt{10} + 6\sqrt{10}

13\sqrt{10}


\sqrt[3]{(3 + 1)^{2}} -  \sqrt{(3 - 2)x^{2}

\sqrt[3]{4^{2}} -  \sqrt{x^{2}

\sqrt[3]{16} - x[tex] \\[tex] \sqrt[3]{8 * 2} - x

\sqrt[3]{8} \sqrt[3]{2} - x


2\sqrt[3]{2} - x




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Answer:

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Step-by-step explanation:

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Solve for n in the literal equation a(n-2)+5=bn
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Answer:

<u><em>Answer is below</em></u>

Step-by-step explanation:

<em><u>a(n-2)+5=bn</u></em>

<em><u>Add -bn to both sides</u></em>

<em><u>an-2a+5+(-bn)=bn+(-bn)</u></em>

<em><u>an-bn-2a+5=0</u></em>

<em><u>add two a to both sides</u></em>

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<em><u>an−bn+5=2a</u></em>

<em><u>Add -5 to both sides</u></em>

<em><u>an−bn+5+(-5)=2a+(-5)</u></em>

<em><u>an−bn=2a−5</u></em>

<em><u>Factor out our variable</u></em>

<em><u>n(a−b)=2a−5</u></em>

<em><u>Divide both sides by a-b</u></em>

<em><u>n(a-b)/a-b=2a-5/a-b</u></em>

<em><u>n=2a-5/a-b</u></em>

<em><u>Hope this helps</u></em>

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