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3 years ago

Efectuati calculele:

1 answer:

8 0

$\sqrt{(5 - 1)^{2}} + \sqrt{20}$

$\sqrt{4^{2}} + \sqrt{4 * 5}$

$\sqrt{16} + \sqrt{4} \sqrt{5} 
$

$4 + 2 \sqrt{5} 
$

$4\sqrt{5} + 2 \sqrt{5} 
$

$6 \sqrt{5}$

$\sqrt{(10 - 3)^{2}} + \sqrt{20 * 18}$

$\sqrt{7^{2}} + \sqrt{4 * 9 * 5 * 2}$

$\sqrt{49} + \sqrt{36 * 10}$

$7 + \sqrt{36}\sqrt{10}$

$7 + 6\sqrt{10}$

$7\sqrt{10} + 6\sqrt{10}$

$13\sqrt{10}$

$\sqrt[3]{(3 + 1)^{2}} - \sqrt{(3 - 2)x^{2}$

$\sqrt[3]{4^{2}} - \sqrt{x^{2}$

$\sqrt[3]{16} - x[tex] \\[tex] \sqrt[3]{8 * 2} - x$

$\sqrt[3]{8} \sqrt[3]{2} - x
$

$2\sqrt[3]{2} - x$

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A bank advertises that it compounds money quarterly and that it will take Double your money in 10 years. what is the interest-ra

S_A_V [24]

The interest rate is 6.992%, if a bank advertises that it compounds money quarterly and that it will take Double your money in 10 years.

Step-by-step explanation:

The given is,

Compounds money quarterly

Double your money in 10 years

Step:1

Formula to calculate future investment with compounded quarterly,

$A =P(1+\frac{r}{n} )^{nt}$ ...............................(1)

Where, A - Future amount

P - Initial investment\

r - Rate of interest

n - No. of compounding in a year

t - No. of years

Step:2

Let, P = X

A = 2X ( Double your money )

From given, n - 4 ( for compounding quarterly )

t - 10 years

From equation (1)

$2X =X(1+\frac{r}{4} )^{(4)(10)}$

$\frac{2X}{X} =(1+\frac{r}{4} )^{(4)(10)}$

$2 =(1+\frac{r}{4} )^{40}$

Take root $40^{th}$ root on both side,

$\sqrt[40]{2} = (1+\frac{r}{4} )$

$1.017479692 = (\frac{4+r}{4} )$

$(1.017479692)(4) = (r+4)$

$4.06992=(r+4)$

$r = 4.06992 -4$

$r =( 0.06992)(100)$

r = 6.992 %

Result:

The interest rate is 6.992%, if a bank advertises that it compounds money quarterly and that it will take Double your money in 10 years.

3 0

3 years ago

If a=12 and b=23 what is the area of pencil decoration

Allushta [10]

I think the answer is 276
12 * 23 = 276
hope it helps

7 0

3 years ago

Read 2 more answers

Determine the equations of the vertical and horizontal asymptotes, if any, for g(x)=x-2/x^2+4x+3

KatRina [158]

Answer:

Step-by-step explanation:

$g(x)=\dfrac{x-2}{x^2+4x+3}\\\\vertical\ asymptote:\\\\x^2+4x+3=0\\x^2+x+3x+3=0\\x(x+1)+3(x+1)=0\\(x+1)(x+3)=0\iff x+1=0\ \vee\ x+3=0\\\\\boxed{x=-1\ \vee\ x=-3}\\\\horizontal\ asymptote:\\\\\lim\limits_{x\to\pm\infty}\dfrac{x-2}{x^2+4x+3}=\lim\limits_{x\to\pm\infty}\dfrac{x^2\left(\frac{1}{x}-\frac{2}{x^2}\right)}{x^2\left(1+\frac{4}{x}+\frac{3}{x^2}\right)}=\lim\limits_{x\to\pm\infty}\dfrac{\frac{1}{x}-\frac{2}{x^2}}{1+\frac{4}{x}+\frac{3}{x^2}}=\dfrac{0}{1}=0\\\\\boxed{y=0}$

4 0

3 years ago

What is the solution to x3 = 64? A 4 B 8 C 16 D 21

dedylja [7]

Answer:

Option A

Step-by-step explanation:

I am assuming that '3' is an exponent.

$x^3=64\\\\\sqrt[3]{x}=\sqrt[3]{64}\\\\\boxed{x=4}$

Hope this helps.

6 0

3 years ago

A polygraph (lie detector) is an instrument used to determine if an individual is telling the truth. These tests are considered

Leya [2.2K]

Answer:

A) P(Type I error) = 0.045

B) P(Type II) error = 0.1

Step-by-step explanation:

We are told that the reliability of the test is 90% reliable.

Also, we are told that the probability that the test erroneously detects a lie even when the individual is actually telling the truth is 0.045.

Thus;

A) To calculate the probability of type I error:

From statistics, in this question we can say that the probability of a type I error is the probability that the test will erroneously detect a lie even though the individual is actually telling the truth. Thus;

Probability of (type I error) = P(rejecting true null) = 0.045

B) For probability of type II error, it is defined as the error where we accept a null hypothesis that is false. We can say that it produces a false negative and the formula is;

P(Type II) error = 1 - reliability

Reliability in the question is 0.90

Thus;

P(Type II) error = 1 - 0.9

P(Type II) error = 0.1

3 0

3 years ago