The width of the cooling tower at the base of the structure will be A. 36 meters.
<h3>How to calculate the width?</h3>
From the information given, the towers walls are modeled by x²/324 - (y² - 90)²/1600.
Therefore, the width of the cooling tower at the base of the structure will be:
= 2 × ✓324
= 2 × 18
= 36
In conclusion, the width is 36 meters.
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12 minutes because 80-20 is 60 and 60 divides by 5 is 12
Answer:
<h2>
AB is around 33.18</h2><h2>
BC is around 15.58 </h2>
Step-by-step explanation:
adjacent/hypotenuse is sine:
cos(28 degrees)=29.3/x
cos(28 degrees)*x=29.3
x=29.3/cos(28 degrees)
x=around 33.18
AB is around 33.18
opposite/adjacent is tangent
tan(28 degrees)=x/29.3
tan(28 degrees)*29.3=x
x=tan(28 degrees)*29.3
x=around 15.58
BC is around 15.58
In a parallelogram, the opposite angles are equal and the sum of the angles is 360 degrees.
W = Z and Y = X
3y = 3x
Y = X = y
3y + y + 3x + x = 360
3x + x + 3x + x = 360
8x = 360
x = 360/8 = 45
Therefore, x = 45; y = 45
M=2/5 , (0,3)
use y= mx+c , find c first.
-3 = (2/5) 0 + c
c = -3
Thus the equation will be y=(2/5)x - 3.
or in some case,
(y1-y)=m(x1-x)
(-3-y)=(2/5)(0-x)