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3 years ago

When I use

Computers and Technology

1 answer:

slega [8]3 years ago

5 0

Answer:

If it works then no, if it doesn't then yes

Explanation:

Code Academy probably runs either way because it is not taking this as a intense class.

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Write a method called all Less that accepts two arrays of integers and returns true if each element in the first array is less t

GaryK [48]

Answer:

The program to this question can be given as:

Program:

#include<iostream> //header file

using namespace std; //using name space

bool allLess (int arr1[], int arr2[]) //defining method allLess

{

int a,b; //define variable

a= *(&arr1 + 1) - arr1; //hold length of arr1

b= *(&arr2 + 1) - arr2; //hold length of arr2

if(a!=b) //checking condition

{

return 1; //return value

}

for(int i=0; i<a; i++) //loop

{

if( arr1[i]>=arr2[i]) //checking condition

{

return 1; //return value

}

return 0; //return value

}

int main() //define main method.

{

int arr1[]={1,2,3,4,5}; //define array arr1 and assign value.

int arr2[]={4,5,6,7,8}; //define array arr2 and assign value.

cout<< allLess(arr1,arr2); //function calling

return 0;

}

Output:

Explanation:

The Explanation of the C++ language program can be given as follows:

In the above program firstly we include the header file. Then a method is defined that is "allLess" this method accepts two arrays that are "arr1 and arr2". This function returns a boolean value that is true or false.
Inside a function, we define a conditional statement and a loop in the if block we check the length of the arr1 array variable is not equal to arr2 array length. if this condition is true it will return false.
In the loop, we define another if block in this block we check that if arr1 array elements are grater then equal to arr2 array element if this condition is true it will return false. At the end of both if block and loop the function will return a value that is "true".
In the main method, we define two arrays and pass to the function and use (cout function) for print return value.

8 0

3 years ago

A simple way to think of the Excel application is as a giant ______.

Naddik [55]

Spreadsheet ......zzzzzz

8 0

3 years ago

Read 2 more answers

Determine the number of character comparisons made by the brute-force algorithm in searching for the pattern GANDHI in the text

leonid [27]

Answer:

Total number of character comparison = 43

Explanation:

Using the Brute force algorithm

The string of n characters is known as text, and the string of m characters is known as the pattern.

From the given information:

The text (n)=THERE_IS_MORE_TO_LIFE_THAN_INCREASING_ITS_SPEED

The pattern (m) = GANDHI

The total no of characters that we have in the text = 47

The total number of characters in pattern = 6

For a brute force algorithm;

Since; the first character of the pattern does not exist in the text, then the number of trials made can be attempted can be expressed as = n – m + 1

= 47 – 6 + 1

= 47 – 5

= 42

Thus; the algorithm will attempt the trial 42 times.

Now, for loop in the algorithm to run 42 times, the G in the pattern will have to align against the for T in the text, and in the last case, it will be aligned against the last space.

On each attempted trial, the algorithm will make one unsuccessful comparison.

However, at the trial at which the G in the pattern Is aligned with the G in the text, there will be two successful comparisons.

Hence, we can calculate the total number of character comparison as follows:

Total number of character comparison = $\mathbf{\bigg ( ( 42 - (no. \ of \ failed \ comparison) ) \times 1 + (1 \times ( Two \ successful \ comparisons) ) \bigg ) }$