3 years ago

Find the inverse for this relation: { (1, -3), (-2, 3), (5, 1), (6, 4) }

Mathematics

1 answer:

worty [1.4K]3 years ago

7 0

Answer:

(-3,1), (3,-2), (1,5), (4,6)

Step-by-step explanation:

For finding and inverse of a relationship, you simply just need to swap the x and y values. So the x will go into the y value and the y value will go into the x value.

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<img src="https://tex.z-dn.net/?f=%285%5E%7B3%7D%29%5E%7B-3%7D" id="TexFormula1" title="(5^{3})^{-3}" alt="(5^{3})^{-3}" align="

morpeh [17]

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}$

$( { {5}^{3} })^{ - 3} \\ \\ which\:means \:that \: {5}^{3}\: is \:multiplied \:thrice\: with\: itself\\ \\ = {5}^{3 \times - 3} \\ \\ = {5}^{ - 9} \\ \\= \frac{1}{ {5}^{9} } \\ \\ = \frac{1}{5 \times 5 \times 5 \times 5 \times 5 \times 5 \times 5 \times 5 \times 5} \\ \\ = \frac{1}{1953125}$

<u>Note</u>:-

$( { {a}^{m} })^{n} = {a}^{m \times n}$

${a}^{ - m} = \frac{1}{ {a}^{m} }$

$\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{!}}}}}$

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