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Stels [109]
3 years ago
10

What is the midpoint of a segment with endpoints at (−4, −8) and (8, 10)? A.(−6, −9) B.(−6, 1) C.(2, −9) D.(2, 1)

Mathematics
1 answer:
spayn [35]3 years ago
3 0

\text{The formula of the midpoint of segment AB:}\\\\\left(\dfrac{x_A+x_B}{2};\ \dfrac{y_A+y_B}{2}\right).\\\\\text{We have the points}\ A(-4,\ -8)\ \text{and}\ B(8,\ 10).\ \text{Substitute:}\\\\x=\dfrac{-4+8}{2}=\dfrac{4}{2}=2\\\\y=\dfrac{-8+10}{2}=\dfrac{2}{2}=1\\\\Answer:\ \boxed{D.\ (2,\ 1)}

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Answer: Option C

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Step-by-step explanation:

Whenever we have a main function f(x) and we want to transform the graph of f(x) by moving it vertically then we apply the transformation:

k (x) = f (x) + b

If b> 0 then the graph of k(x) will be the graph of f(x) displaced vertically b units down.

If b> 0 then the graph of k(x) will be the graph of f(x) displaced vertically b units upwards.

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Then, to move its vertex 7 units down we apply the transformation:

k (x) = f (x) - 7\\\\k (x) = x ^ 2 -7.

Then the function k(x) that will have its vertex 7 units below f(x) is

k (x) = x ^ 2 -7

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