Answer:
(a+1)(a+27)
Step-by-step explanation:
Trinomials are three term algebraic expressions typically featuring variables to exponent powers. To break these trinomials down we factor them using the diamond method or GCF. The diamond method states that for a trinomial multiply A*C then find two numbers which multiply to this number and add to B. When you find those numbers, write them as
.
A=1, C=27
A*C=27 and add to B=28 which 1 and 27 satisfy
The factors are (a+1)(a+27)
As per the given question, the expression of the function is as:
Now, as per the definition of zeros, the zero is that value of x which when plugged into the function should make the function zero (it is also called "making the function vanish"). <u>In our case, plugging in "zero values" of x should make the numerator zero without making the denominator zero.</u> Now, if we plug in the given values of x, which are x=-1, x=2 and x=4 in the function we see that the <u>numerator does not become a zero but the denominator does</u>.
Thus, x=-1, x=2 and x=4 are not the zeros of the function and therefore, Sue is wrong. However, we do have discontinuities at the aforementioned values of x because the denominator becomes a zero at those points and as per the definition of a discontinuity the denominator should be a zero at that point. Therefore, Ed is correct.