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Zarrin [17]
1 year ago
5

You have just signed up for a broadband home internet service that uses coaxial cable. which connector type will you most likely

use?
Mathematics
2 answers:
vampirchik [111]1 year ago
5 0

F type connector

  • The F-connector is a coaxial RF connector commonly used for "wireless" terrestrial television, cable television, and common for satellite television and cable modems, usually with RG-6/U cable or with RG -59 / U.

  •  F connector is also known as threaded connector. There are two main types: 7mm (6.8mm) is the most common and  used in coaxial cable, and 5mm connector  is used in  thin coaxial cable commonly used in satellite system.

  • The F-connector is an accessory that connects a coaxial cable to an electronic device or  wall outlet.

  • Type F connectors are highly mechanical and electrically stable coaxial screw connectors  for cable television (CATV), set-top boxes, cable modems and satellite television applications up to 4 GHz

Learn more about wire here

brainly.com/question/15246898

#SPJ4

Eddi Din [679]1 year ago
3 0

Answer:

F type connector

Step-by-step explanation:

Use an F-type connector for broadband cable connections that use coaxial cable.

The F connector is a coaxial RF connector commonly used for "over the air" terrestrial television, cable television and universally for satellite television and cable modems,

#SPJ4

Learn more on

brainly.com/question/14391417

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PLSS HELP 25 POINTS AND BRAINLIEST
photoshop1234 [79]

Answer:

136

Step-by-step explanation:

7*5=35

35+35=70

1/2*6*4=12

12+12=24

6*7=42

70+42+24=136

sorry if it is wrong.

3 0
3 years ago
Read 2 more answers
A quality control engineer is interested in estimating the proportion of defective items coming off a production line. In a samp
fenix001 [56]

Answer:

The lower bound of a 99% C.I for the proportion of defectives = 0.422

Step-by-step explanation:

From the given information:

The point estimate = sample proportion \hat p

\hat p = \dfrac{x}{n}

\hat p = \dfrac{55}{100}

\hat p = 0.55

At Confidence interval of 99%, the level of significance = 1 - 0.99

= 0.01

Z_{\alpha/2} =Z_{0.01/2} \\ \\ = Z_{0.005} = 2.576

Then the margin of error E = Z_{\alpha/2} \times \sqrt{\dfrac{\hat p(1-\hat p)}{n}}

E = 2.576 \times \sqrt{\dfrac{0.55(1-0.55)}{100}}

E = 2.576 \times \sqrt{\dfrac{0.2475}{100}}

E = 2.576 \times0.04975

E = 0.128156

E ≅ 0.128

At 99% C.I for the population proportion p is: \hat p - E

= 0.55 - 0.128

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Thus, the lower bound of a 99% C.I for the proportion of defectives = 0.422

6 0
3 years ago
Solve for c.<br>C= [?]<br>Enter the number<br>that goes beneath<br>the radical symbol.<br>​
photoshop1234 [79]

Answer:

c=45

Step-by-step explanation:

by the pythagorean theorem, c = sqrt(3^2+6^2) = sqrt(9+36) = sqrt(45)

Therefore, c=45.

5 0
3 years ago
Please Help POINTS: 15 (look at the screenshot below)
lord [1]
D: 2/1

EXPLANATION:
Jacob has 8

Antonio has 4.

8/4 is the ratio

8/4 can be simplified to 2/1

Hope this helps!
6 0
3 years ago
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Anarel [89]
So you don't have to use pi for this problem you can do L*W
So you can do 20*36
3 0
3 years ago
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