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Zarrin [17]
1 year ago
5

You have just signed up for a broadband home internet service that uses coaxial cable. which connector type will you most likely

use?
Mathematics
2 answers:
vampirchik [111]1 year ago
5 0

F type connector

  • The F-connector is a coaxial RF connector commonly used for "wireless" terrestrial television, cable television, and common for satellite television and cable modems, usually with RG-6/U cable or with RG -59 / U.

  •  F connector is also known as threaded connector. There are two main types: 7mm (6.8mm) is the most common and  used in coaxial cable, and 5mm connector  is used in  thin coaxial cable commonly used in satellite system.

  • The F-connector is an accessory that connects a coaxial cable to an electronic device or  wall outlet.

  • Type F connectors are highly mechanical and electrically stable coaxial screw connectors  for cable television (CATV), set-top boxes, cable modems and satellite television applications up to 4 GHz

Learn more about wire here

brainly.com/question/15246898

#SPJ4

Eddi Din [679]1 year ago
3 0

Answer:

F type connector

Step-by-step explanation:

Use an F-type connector for broadband cable connections that use coaxial cable.

The F connector is a coaxial RF connector commonly used for "over the air" terrestrial television, cable television and universally for satellite television and cable modems,

#SPJ4

Learn more on

brainly.com/question/14391417

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The median of the values of the data set is h. If 625 were subtracted from each of the values in the data set what would be the
Alika [10]
B
it always turns to a negative

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3 years ago
The reported unemployment is 5.5% of the population. what measurement scale is used to measure unemployment? nominal ordinal int
kirill115 [55]

The answer is interval or ratio. In interval level of measurement, the distances between have attributes does have a meaning. The best example to be used here is temperature. The distance from 40-50 is like the distance from 70-80. While in <span>ratio level of </span>measurement, there is constantly an absolute zero that is significant. Meaning, that you can build a meaningful fraction (or ratio) with a ratio variable. 

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3 years ago
6. a) Calculate the areas of the three squares. b) Is the triangle a right triangle? Explain. 3 cm 4 cm 2 cm
viktelen [127]

Answer

The total area of the squares = 29 square cm

The triangle is not a right-angled triangle

Step-by-step explanation:

We are given three squares

The first square has a length of 4cm

The second square has a length of 3cm

The third square has a length of 2cm

Part A

Total area = Area of square 1 + Area of square 2 + Area of square 3

Area of a square = l^2

Where l is the length of the square

Area of a square 1 = 4^2

Area of a square = 16 square cm

Area of square 2 = 3^2

Area of square 2 = 9 square cm

Area of square 3 = 2^2

Area of square 3 = 4 square cm

Total area of the square = 16 + 9 + 4

The total area of the square = 29 square cm

Hence, the total square of the figure is 29 square cm

Part B

\begin{gathered} \text{ To proof if the triangle is a right angled triangle} \\ \text{ We n}eed\text{ to appy Pythagora's theor}em \\ \text{Hypotenus}^2=perpendicular^2+base^2 \\ \text{Hypotenus = 4}cm \\ \text{Perpendicular =3cm} \\ \text{Base = 2cm} \\ 4^2=3^2+2^2 \\ 16\text{ = 9 + 4} \\ 16\text{ }\ne\text{ 13} \\ \text{ Since the hypotenus is not equal to the summation of the perpendicular and base} \\ \text{Hence, the triangle is a not right angled triangle} \end{gathered}

6 0
1 year ago
Jessica is getting ready for college she needs to have an overall grade of 85 in her Math class to qualify for the college that
VLD [36.1K]
So,

Her average so far is the sum of the five scores divided by the number of tests she has taken so far.

(87 + 81 + 85 + 90 + 78)/5 = 84.2

(87 + 81 + 85 + 90 + 78)/5 < 85 :(

She will not get into that college if she doesn't increase her average on the last test.

85 - 84.2 = 0.8

0.8(5) = 4.0

On her last test, she needs to score 4 points higher than her current average in order to get into the college.

84.2 + 4 = 88.2

Jessica needs to score at least 88.2 on her last test.

5 0
3 years ago
G/e^2-r=m-y please solve for e
allochka39001 [22]
Move r to the right side of the equation, G/e^2=m-y+r. Multiply both sides by e^2, G=(m-y+r)*e^2. Then divide both sides by m-y+r (it cannot be 0), G/(m-y+r)=e^2. Then e=+-\sqrt(G/(m-y+r)).
7 0
3 years ago
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