Answer:
circle a and circle b must exist
Step-by-step explanation:is circle a and circle b did not exist this question would not be one
The first month has the equation raised to 11 which is the number of months left in the period.
So each month the equation would be the same except it would be raised to 1 less than the previous month.
Month 2 = 50(1.003)^10
Month 3 = 50(1.003)^9
Month 4 = 50(1.003)^8
Month 5 = 50(1.003)^7
Month 6 = 50(1.003)^6
Month 7 = 50(1.003)^5
Month 8 = 50(1.003)^4
Month 9 = 50(1.003)^3
Month 10 = 50(1.003)^2
Month 11 = 50(1.003)^1
Month 12 = 50(1.003) ( the last month would not be raised to anything)
Answer: Irregular Hexagon
Answer:
Step-by-step explanation:
m∠2=71° because they are vertical angles so are congruent
those 4 angles in the midle will add up to 360°
∠3+∠5=360-2*71=218 so
m∠3=218/2=109°
m∠5=109°
mostly use that the sum of angles in a Δ add to 180
m∠1=180-47-71=62°
m∠4=180-109-36=35°
m∠6=180-42-109=29°
use that opposide ∠s in a quadrinateral add to 180
m∠7=180-47-35-29= °69
m∠8=180-42-62-36= °40
