<span>Answer:
Roma Sherry drove 330 miles from her hometown to Tucson. During her return trip, she was able to increase her speed by 11 mph. If her return trip took 1 hour less time, find her original speed and her speed returning home.
:
Let s = original speed
then
(s+11) = return speed
:
Write a time equation: Time = distance%2Fspeed
:
Original time = return time + 1 hr
330%2Fs = 330%2F%28%28s%2B11%29%29 + 1
:
Multiply equation by s(s+11) and you have:
330(s+11) = 330s + s(s+11)
:
330s + 3630 = 330s + s^2 + 11s
:
0 = 330s - 330s + s^2 + 11s - 3630
:
A quadratic equation:
s^2 + 11s - 3630 = 0
Factor this to:
(s + 66)(s - 55) = 0
Positive solution
s = 55 mph is original speed.
:
Find the time
330/55 = 6 hr, original time
and
330/66 = 5 hrs, faster time; confirms our solution.</span>
S+7. Tell your teacher never to use s as a variable ever again.
1 = x(2) - 2x - 3
1 = 2x + -2x + - 3
1 = (2x + -2x) + (-3)
1 = -3
1 - 1 = -3 -1
0 = -4
No solutions
Answer:
- 7/24
Step-by-step explanation:
Step 1:
3/8 = r + 2/3
Step 2:
9/24 = r + 16/24
Step 3:
9/24 - 16/24 = r
Answer:
- 7/24 = r
Hope This Helps :)
