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Vlad1618 [11]
3 years ago
12

In your own words, explain the process of how you would divide 2/3 by 1/2

Mathematics
2 answers:
tensa zangetsu [6.8K]3 years ago
8 0

Answer:

Down below :) Hope this helps!

Step-by-step explanation:

To divide fractions, you have to flip the second fraction.

For example, 2/3 divided by 1/2 is the same thing as 2/3 x 2/1, you have to flip the second fraction. When you do this, your answer will be 4/3 or 1 1/3.

gtnhenbr [62]3 years ago
8 0

Answer:

i would multiply the 2 numerators first then the 2 bottom numbers or i would factor it by a common denominatior which is 6

Step-by-step explanation:

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When a number is added to 1/5 of itself, the result is 24. The equation that models this problem is n +1/5 n = 24. What is the v
Lady_Fox [76]

For this case we must find the value of n of the following equation:

n + \frac {1} {5} n = 24

Taking common factor "n" from the left side of the equation we have:

n (1+ \frac {1} {5}) = 24\\n \frac {6} {5} = 24

Multiplying by 5 on both sides of the equation:

6n = 120

Dividing between 6 on both sides of the equation:

n = 20

Thus, the value of n is 20.

Answer:

n = 20

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Answer:

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Step-by-step explanation:

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3 years ago
A researcher recorded the shooting percentage of 28 professional basketball players in each of four quarters in a game. What are
mariarad [96]

Answer: c) 81

Step-by-step explanation:

The formula to calculate the degrees of freedom error for a one-way within-subjects ANOVA is given by :-

\text{df}=(n-1)\times(k-1)

Given : A researcher recorded the shooting percentage of 28 professional basketball players in each of four quarters in a game.

Here , n= 28 and k= 4

Then, the degrees of freedom error for a one-way within-subjects ANOVA will be :-

\text{df}=(28-1)\times(4-1)=27\times3=81

Hence, the degrees of freedom error for a one-way within-subjects ANOVA are 81.

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If the function y = sinx is transformed to y = 3 sine (two-thirds x), how do the amplitude and period change?
icang [17]

Answer:

Amplitude increases and the period decreases

Step-by-step explanation:

Here, we are to compare amplitude change and period change

The first equation is;

y = sin x

The second is

y = 3 sine (2/3)x

Generally, the equation of a sine graph can be written as;

y = a sin (bx + c)

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In the first equation , a = 1 while in the second , a = 3 ; This shows an amplitude increase

In the first equation, b = 1 while in the second equation b = 2/3; this shows a period decrease

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A social psychologist predicted that ratings of an individual’s social desirability would be influenced by their physical attrac
marshall27 [118]

Answer:

It is stated in the query that the more attractive the individual, the higher their rank of desirability.

Step-by-step explanation:

This means that we should conclude that the alternative explanation of "higher degree of desire contributes to higher levels of social attractiveness"

In the event of a null hypothesis, we will believe that the degree of attractiveness has no impact on the score of cultural desirability.

(1) Null hypothesis:- The level of attraction does not have an impact on the rating of social desirability.

(2) Alternate hypothesis:- The level of attraction has a positive effect on the ranking of social desirability.

(3) The error of Type I is characterized as the rejection of the true null hypothesis. Therefore, in this case, the type I mistake would be that "the level of attraction has a positive effect on the rating of social desirability while the level of attraction does not have an impact on the rating of social desirability."

(4) The error of type II is characterized as the failure to reject the false null hypothesis. Thus, in this situation, the Type II error would be that "the level of attraction has no impact on the rating of social desirability while the real level of attraction has a positive effect on the rating of social desirability."

(5) We know that the likelihood of having a Form I error is equal to the degree of significance (in percent terms). The significance level, in this case, is 0.05, so the likelihood of making a form I error is 0.05 * 100=5 percent.

Therefore, there is a 5 percent risk of making a Type I mistake.

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