x is less than or equal to -4 or x is greater than or equal to 5
x <= -4 or x>= 5
There is no intersection of both inequalities when we graph it in number line So, we write the interval notation separately for each inequality
for x<=-4 , x starts at -4 and goes to -infinity because we have less than symbol. Also we have = sign so we use square brackets
Interval notation is (-∞ , -4]
for x>= 5 , x starts at 5 and goes to infinity because we have greater than symbol. Also we have = sign so we use square bracket at 5
Interval notation is [5 , ∞)
Now combine both notation by a 'U' symbol Union
(-∞ , -4] U [5 , ∞)
Answer:
Correct answer: F. graph F or x ∈ |-5 ; 5| (including endpoints)
Step-by-step explanation:
Let us first define the absolute value:
| x | = 1. { x with condition x ≥ 0 }
or 2. { - x with condition x < 0 }
This is a linear inequality
1. x ≤ 5 ∧ x ≥ 0 ⇒ 0 ≤ x ≤ 5 or interval x ∈ |0 ; 5| (including endpoints)
2. - x ≤ 5 when we multiply both sides of the equation by -1 we get:
x ≥ -5 ∧ x < 0 ⇒ -5 ≤ x < 0 or interval x ∈ |-5 ; 0) (including -5)
The solution to this linear inequality is the union of these two intervals:
x ∈ |-5 ; 0) ∪ |0 ; 5| ⇒ x ∈ |-5 ; 5| (including endpoints)
x ∈ |-5 ; 5| (including endpoints)
God is with you!!!
Answer:
C (0,1)
D (0,0)
E (0,-1)
G (0,5)
Step-by-step explanation:
The x coordinate has to be a zero so that the point could be on the Y-axis
Explanation:
Divide the negative 16 by 2= -8
Then square -8
So the missing constant is 64
The perfect square would be (x-8)^2
