Write the first four terms of the sequence<br><br><br> the rule is: start at 3 1/8, subtract 3/4

Evaluate the expression 3x^2+4x^3 when x=4.

larisa [96]

Step-by-step explanation:

304

plug 4 in for x

3(4)^2 + 4(4)^3 = 304

48 + 256 = 304

6 0

2 years ago

NO LINKS!!!<br><br>Find the indicated side for each triangle below:

pogonyaev

Problem 5

Apply the Law of Sines

s/sin(S) = r/sin(R)

s/sin(78) = 10/sin(48)

s = sin(78)*10/sin(48)

s = 13.162274

<h3>Answer: 13.162274 approximately</h3>

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Problem 6

Use the Law of Sines here as well.

x/sin(X) = y/sin(Y)

x/sin(53) = 6/sin(22)

x = sin(53)*6/sin(22)

x = 12.791588

<h3>Answer: 12.791588 approximately</h3>

8 0

2 years ago

Read 2 more answers

What is 1 & 5/7 times 2 & 3/4

VARVARA [1.3K]

The solution of $1\frac{5}{7} \times 2\frac{3}{4}$ is $\frac{33}{7} \text{ or } 4.714$

<em><u>Solution:</u></em>

Given that we have to find the solution of given expression

Given expression is:

$1\frac{5}{7} \times 2\frac{3}{4}$

Let us first convert the mixed fraction to improper fraction

Multiply the whole number part by the fraction's denominator.

Add that to the numerator.

Then write the result on top of the denominator.

Therefore,

$1\frac{5}{7} = \frac{1 \times 7+5}{5} = \frac{12}{5}$

$2\frac{3}{4} = \frac{2 \times 4+3}{4}=\frac{11}{4}$

Now the expression becomes,

$1\frac{5}{7} \times 2\frac{3}{4} = \frac{12}{7} \times \frac{11}{4}$

Solve and simplify the above expression

$1\frac{5}{7} \times 2\frac{3}{4} = \frac{12}{7} \times \frac{11}{4} = \frac{33}{7}\\\\1\frac{5}{7} \times 2\frac{3}{4} = \frac{33}{7}$

In decimal form we get,

$\frac{33}{7}=4.714$

Thus the solution to given expression is found

5 0

3 years ago

Find the perimeter of a triangle with points A(1,2), B(1,8), and C(5,5) on a Cartesian coordinate plane.

Assoli18 [71]

Check the picture below.

the distance from 1,2 to 1,8 is simply 6 units, we can read that off the grid. Now let's see what the other distances are, and add them all up to get the perimeter.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{2})\qquad C(\stackrel{x_2}{5}~,~\stackrel{y_2}{5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AC=\sqrt{(5-1)^2+(5-2)^2}\implies AC=\sqrt{4^2+3^2} \\\\\\ AC=\sqrt{25}\implies AC=5 \\\\[-0.35em] ~\dotfill$

$\bf B(\stackrel{x_1}{1}~,~\stackrel{y_1}{8})\qquad C(\stackrel{x_2}{5}~,~\stackrel{y_2}{5}) \\\\\\ BC=\sqrt{(5-1)^2+(5-8)^2}\implies BC=\sqrt{4^2+3^2} \\\\\\ BC=\sqrt{25}\implies BC=5 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{perimeter}{6+5+5\implies 16}~\hfill$