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Enter your answer and show all the steps that you use to solve this problem in the space provided. A.Solve a–9=20 B.Solve b–9&gt

Goryan [66]

Answer:

A) The value of a is 29.

B) The value of b is greater than 29.

C) In both part A and part B we have used a common property which is addition property and that we have add 9 on both side of equation in both parts.

D) The value of a in part A is equal to 29 whereas in part B the value of b is greater than 29.

Step-by-step explanation:

Solving for Part A.

Given,

$a-9=20$

We have to solve for a.

$a-9=20$

By using addition property of equality, we will add both side by 9;

$a-9+9=20+9\\a=29$

Hence the value of a is 29.

Solving for Part B.

Given,

$b-9>20$

We have to solve for b.

$b-9>20$

By using addition property of inequality, we will add both side by 9;

$b-9+9>20+9\\b>29$

Hence the value of b is greater than 29.

Solving for Part C.

In both part A and part B we have used a common property which is addition property and that we have add 9 on both side of equation in both parts.

Solving for Part D.

The value of a in part A is equal to 29 whereas in part B the value of b is greater than 29.

5 0

3 years ago

8(y+4)=7y+38 asap pls

Readme [11.4K]

Distribute
remember a(b+c)=ab+ac
8(y+4)=8(y)+8(4)=8y+32

8y+32=7y+38
minus 7y both sides
y+32=38
mius 32 oth sides
y=6

8 0

2 years ago

Chooose the like terms 3h,i,4i answer

skelet666 [1.2K]

I and 4i
let's say if you have i you can automatically think there is a one in front of it so one term like this (i) could look like this 1i and any number with the same variable or letter are like terms
hope this helps

8 0

3 years ago

John is expanding these two brackets.

Elan Coil [88]

Answer: Um, the answer is B, and C?

Step-by-step explanation:

5 0

3 years ago

How to do question 22?

Aleks04 [339]

Answer:

A = 20sinθ(6 + 5 cosθ) cm²

Step-by-step explanation:

Drop perpendiculars DE and CF to AB.

Then, we have congruent triangles ADE and BCF, plus the rectangle CDEF.

The formula for the area of the trapezium is

A = ½(a + b)h

DE = 10sinθ

AE = 10cosθ

BF = 10cosθ

EF = CD = 12 cm

AB = AE + EF + BF = 10cosθ + 12 + 10 cosθ = 12 + 20cosθ

A = ½(a + b)h

= ½(12 +12 + 20 cosθ) × 10 sinθ

=(24 + 20 cosθ) × 5 sinθ

= 4(6 + 5cosθ) × 5sinθ

= 20sinθ(6 + 5 cosθ) cm²

6 0

3 years ago

Anyo ne can ms on this navneet175285 e mail ​

Anyo ne can ms on this navneet175285 e mail