a. What percent of people earn less than $40000?
Solution: Let S be the random variable of a salary of employee (in $), S ~ N(50000,20000). Then the random
variable X =−50000
20000
~N(0,1).
( < 40000) = ( <
40000 − 50000
20000 ) = ( < −0.5) = (−0.5) = 0.3085375.
Here Φ(x) denotes the cumulative distribution function of a standard normal distribution.
Answer: 31%.
b. What percent of people earn between $45000 and $65000?
Solution:
(45000 < < 65000) = (
45000 − 50000
20000 < <
65000 − 50000
20000 ) = (−0.25 < < 0.75)
= (0.75) − (−0.25) = 0.7733726 − 0.4012937 = 0.3720789.
Answer: 37%.
c. What percent of people earn more than $70000?
Solution:
( > 70000) = ( >
70000 − 50000
20000 ) = ( > 1) = 0.8413447.
Answer: 84%.
Answer:
why no links? also I think the answer is 5 but I'm just guessing
Answer:
23
Step-by-step explanation:
Answer:
The expression used to find the change in temperature per hour is Algebraic expression
Thus per hour; the temperature falls at the rate of
Step-by-step explanation:
A temperature falls from 0 to
in 
Which expression finds the change in temperature per hour.
From the above given information;
The initial temperature is 0
The final temperature is
The change in temperature is 


Thus;
-12.25 ° = 3.5 hours
To find the change in x° per hour; we have;
x° = 1 hour
The expression used to find the change in temperature per hour is Algebraic expression
From above if we cross multiply ; we have;
(- 12.25° × 1 hour) = (x° × 3.5 hour)
Divide both sides by 3.5 hours; we have:

x° = - 3.5
x° = 
Thus per hour; the temperature falls at the rate of