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Darya [45]
3 years ago
8

Twenty-nine children went to a zoo to photograph some animals. The numbers of children who photographed Lions (L), Monkeys (M) a

nd Zebras (Z) are given as follows: 6 of the children photographed all three 9 photographed Lions and Zebras 2 photographed Monkeys and Lions but not Zebras 3 photographed Lions only 4 photographed Monkeys only 10 photographed Zebras only i. Draw a Venn diagram to show this information. [4] ii. Find all of the children photographed at least one of the three types of animal. [4] iii. Find the number of children that photographed Monkeys and Zebras but not Lions.
Mathematics
1 answer:
kupik [55]3 years ago
7 0

Answer:um 24

Step-by-step explanation:

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Answer:  (sec x – tan x)(csc x + 1).

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2 years ago
A handful of chewing gum contains 5 red pieces out of 11. What is the probability that a randomly selected
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Find the number of pieces that aren't red, by subtracting the red from the total:

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3 years ago
What is the cost of each chicken and what is the cost of each duck
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Answer: $8 chicken $5 duck

Step-by-step explanation:

50x+30y=550

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7 0
3 years ago
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What is the value of a in the equation a = 2 + 3a + 6?
gulaghasi [49]
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3 0
3 years ago
HELP ME PLEASE 10 points!!!!!
atroni [7]

Answer:

x>9

Step-by-step explanation:

Tamika already has $55, which will stay the same independent of how much time passes. Since she deposits $5 per week, we can assign weeks a variable x. The amount of money in her account after x weeks is equal to 55+5x. If she must save over $100, we can create an inequality to solve for how many weeks must pass: 55+5x>100.

The question also asks to solve the inequality:

  1. 55+5x>100
  2. 5x>100-55 (Subtract 55 from each side)
  3. 5x>45
  4. x>9 (Divide each side by 5)

This solution tells us that Tamika must save for more than nine weeks to have more than $100 in her account.

lmk if i made an error, hope this helps!!

3 0
2 years ago
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