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worty [1.4K]
3 years ago
5

Plz help asap math isn't my thing

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
3 0

This is the answer to your following question. Good luck!

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State whether each of the following equations represent growth or decay.
algol [13]

Answer:

ehhh Pfouto math ni

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4 0
3 years ago
5x+2y=22. -2x+6y=3 What is the X coordinate of the solution. Round to the nearest tenth
just olya [345]
Multiply first example by 3 and subtract by second example, you will get the following:

3*(5x + 2y) = 3*22   =>  3*5x + 3*2y = 66      =>  15x + 6y = 66
now subtraction:
(15x + 6y) - (-2x + 6y) = 66 - 3
15x + 6y + 2x - 6y = 63
15x + 2x + 6y - 6y = 63
17x = 63
x = 63/17 ≈ 3.705..... and as it says to round to the nearest tenth our answer would be: x = 3.7
8 0
3 years ago
Given w = 1 + i and z = 1 + i, which number can be added to w to produce z?
9966 [12]

Answer:

C) 0i?????????????

Step-by-step explanation:

They are the same thing why would you need to add anything?

I feel bad searching this up

6 0
3 years ago
Read 2 more answers
How many pounds of a 15% copper alloy must be mixed with 700lb of a 30% copper alloy to maybe a 25.5% copper alloy
lisov135 [29]

Answer:

300\; \rm lb.

Step-by-step explanation:

Let x represent the mass (in pounds) of that 15\% copper alloy required, such that the final mixture would contain 25.5\% copper by mass.

Consider: if x pounds of that 15\% copper alloy is mixed with 700 pounds that 30\% copper alloy, what would be the mass of copper in the mixture?

  • Mass of copper in x pounds of that 15\% copper alloy: (0.15\, x)\; \rm lb.
  • Mass of copper in 700 pounds of that 30\% copper alloy: 700 \times 0.30 = 210\; \rm lb.

Therefore, the mixture would contain (210 + 0.15\, x) \; \rm lb of copper.

The mass of that mixture would be (700 + x)\; \rm lb. The mass fraction of copper in that mixture would be:

\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\%.

This ratio is supposed to be equal to 25.5\%. These two pieces of equations combine to give an equation about x:

\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\% = 25.5\%.

\displaystyle \frac{210 + 0.15\, x}{700 + x} = 0.255.

Simplify and solve for x:

210 + 0.15\, x= 0.255\, (700 + x).

(0.255 - 0.15)\, x= 210 - 0.255 \times 700.

\displaystyle x = \frac{210 - 0.255 \times 700}{0.255 - 0.15} = 300.

Therefore, 300\; \rm lb of that 15\% alloy would be required.

4 0
3 years ago
How do I add mixed numbers<br>8 1/2 +1/6<br>​
sergij07 [2.7K]

Answer:

<u><em>26/3  is your answer as a improper fraction </em></u>

<u><em>8.6 is your answer as a decimal </em></u>

<u><em>8 2/3 is your answer as a mixed number </em></u>

How to add mixed numbers Step-by-step:

1) find the least common denominator

2) find the equivalent fractions  

3) add the the fractions, add the whole numbers

4) write your answer in lowest terms

6 0
3 years ago
Read 2 more answers
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