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VARVARA [1.3K]
3 years ago
10

On a multiple-choice test, each question has 4 possible answers. A student does not know the answers to three questions, so the

student guesses. What is the probability that the student gets all three questions wrong? The probability that the student gets all three questions wrong is . What is the probability that the student gets all three questions right? The probability that the student gets all three questions right is .
Mathematics
1 answer:
olga2289 [7]3 years ago
7 0

Answer:

P(making 3 wrong guesses) = 27/64

P(making 3 right guesses) = 1/64

Step-by-step explanation:

Number of possible answers per question = 4

Number of right answer per question = 1

Number of wrong answers per question = (4 - 1) = 3

Probability = (Number of required outcomes / Number of Total possible outcomes)

A.) probability of guess 3 questions wrong :

Probability of making a wrong guess = (number of wrong options / total number of options

P(making a wrong guess) = 3/4

Therefore,

P(making 3 wrong guesses) = 3/4 × 3/4 × 3/4 = (27/64)

B.) probability of making 3 right guesses:

P(making a right guess) = (number of right options per question / total number of options per question)

P(making a right guess) = 1/4

P(making 3 right guesses) =(1/4 × 1/4 × 1/4) = 1/64

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An example:

So 2 to the power of 15, which we write as 215 = 2 * 2 * 2 * 2 etc... (so we have 15 written 2's in total meaning we will make 14 multiplications) is equal to 32,768.

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Serhud [2]

Answer:

x=19

Step-by-step explanation:

First, you place the numbers in place of the variables in their relative positions using the pythagorean theorem:

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3 years ago
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azamat

For this case we have the following quadratic equation:

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Where:

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Its roots will be given by:

w = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}\\w = \frac {- (- 7) \pm \sqrt {(- 7) ^ 2-4 (6) (- 20)}} {2 (6)}\\w = \frac {7 \pm \sqrt {49 + 480}} {12}\\w = \frac {7 \pm \sqrt {529}} {12}\\w = \frac {7 \pm23} {12}

The roots are:

w_ {1} = \frac {7 + 23} {12} = \frac {30} {12} = \frac {15} {6} = \frac {5} {2}\\w_ {2} = \frac {7-23} {12} = \frac {-16} {12} = - \frac {8} {6} = - \frac {4} {3}

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w_ {1} = \frac {5} {2}\\w_ {2} = - \frac {4} {3}

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