3 years ago

How do I write 10b4 + 3b2 - 11 in quadratic form

Mathematics

1 answer:

Nesterboy [21]3 years ago

4 0

Answer:

46b-11

Step-by-step explanation:

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Step-by-step explanation:

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Answer:

D (last one)

Step-by-step explanation:

You figure out the ordered pair for E which is (3,-4)

Then you apply the rule given in the instructions.

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then -4+5= 1 so y = 1

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lapo4ka [179]

Answer:

A. 1

Step-by-step explanation:

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3 years ago

The solution of a certain differential equation is of the form y(t)=aexp(7t)+bexp(11t), where a and b are constants. The solutio

Solnce55 [7]

Answer:

Step-by-step explanation:

Given that the solution of a certain differential equation is of the form

$y(t) = ae^{7t} +be^{11t}$

Use the initial conditions

i) y(0) =1

$1=a(1)+b(1)\\a+b=1$ ... I

ii) y'(0) = 4

Find derivative of y first and then substitute

$y'(t) = 7ae^{7t} +11be^{11t}\\y'(0) =7a+11b \\7a+11b =4 ...II$

Now using I and II we solve for a and b

Substitute b = 1-a in II

$7a+11(1-a) = 4\\-4a+11 =4\\-4a =-7\\a = 1.75 \\b = -0.75$

Hence solution is

$y(t) = 1.75e^{7t} -0.75e^{11t}$

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3 years ago

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