Answer:
(
h
∘
f
∘
g
)
(
x
)
is known as a composite function. Here's how composite functions work:
let's say that
x
=
1
. Your function
g
(
x
)
=
1
3
(
x
)
now produces a
y
output of
1
3
, since
g
(
1
)
=
1
3
(
1
)
. Within a composite function, the y-value of one function becomes the x-value of the next, like so:
g
(
1
)
=
1
3
⇒
f
(
1
3
)
=
17
3
⇒
h
(
17
3
)
=
17
Therefore,
(
h
∘
f
∘
g
)
(
1
)
=
17
Based on this, to find the function for
(
h
∘
f
∘
g
)
(
x
)
(combined from right to left, by the way), simply replace
x
in
f
(
x
)
with the function
g
(
x
)
, and replace
x
in
h
(
x
)
with the function of
(
f
∘
g
)
(
x
)
, to get
(
h
∘
f
∘
g
)
(
x
)
.
This, simplified, is equal to
2
x
+
15
, and therefore
(
h
∘
f
∘
g
)
(
1
)
=
2
(
1
)
+
15
=
17
Hope that helps!
Answer: The road, crucifix/cross, sidewalks, railroads, and so much more.
Step-by-step explanation: Roads are parallel so that everyone can get to the same place in different lanes. This is important because lines that aren't parallel will inevitably meet, meaning that a highway would eventually merge its two lanes. This happens, but most of the highway is parallel. The same is true of sidewalks and railroads. The crucifix/cross is a Christian symbol, and while I'm not Christian, I'm sure it's important to a lot of people who are.
Answer
25mm of rain fell each second
Step-by-step explanation:
we know that 500 mm fell in 20 minutes
so, we have to divide 500 by 20 giving us the amount of rain that fell each minute:
500/20 = 25
therefore, 25mm of rain fell each minute
hope this helped:)
5.250
To change a fraction to a decimal fraction divide the numerator by the denominator.
that is 21 ÷ 4 = 5.250 ( to 3 decimal places )
Answer:
Step-by-step explanation:
In order to find the answer, let's work backwards to find the original. We have to do the opposite to get to the Raju's age. We will start with his fathers age. (44) Then we will subtract five from it so that it will be divisible by three.
44 - 5 = 39
Then we just have to divide by 3.
44/3 = 13
His age is 13 years old.
