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tensa zangetsu [6.8K]
3 years ago
13

Which number is missing from the following prime factorization expression? 792 = __ x 2 x 2 x 2 x 3 x 11 A. 2 B. 3 C. 5 D. 7

Mathematics
2 answers:
slega [8]3 years ago
8 0

Answer:

i agree, 3 is the answer

Took same test

lions [1.4K]3 years ago
7 0

Answer:

3

Step-by-step explanation:

Evaluate 2 x 2 x 2 x 3 x 11 (better written as 2·2·2·3·11, because "x" is a variable name, not a math operator).

2·2·2·3·11 = 8·33 = 264

Then divide 792 by this 264 to find the final factor:

final factor = 792/264 = 3

Then the prime factorization of 792 is 2·2·2·3·3·11

which we obtained by multiplying 2 x 2 x 2 x 3 x 11 by 3.

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Will mark brainliest if correct :)
Finger [1]

Answer:

d = 12

c = 4

so I think d > c

Step-by-step explanation:

1 x 12 = 12

0.75 x 4 = 3

12 + 3 = 15

8 0
3 years ago
Factor the expression. 3p + 21
bagirrra123 [75]
I believe that the answer is p+7
7 0
3 years ago
At oceanside middle school 110 students tried out for the football team only 80% of the students that tryout make the team how m
Olenka [21]

Step-by-step explanation:

answer is 22 students in the team

<em>how </em><em>do </em><em>u </em><em>get </em><em>it? </em>

you know it is 80% of the students went for try out so you do 100% - 80% give you 20% students the number of students in the team already. so you do 20 / 100 x 110 students which already in the whole school over 1 which would give it 22

3 0
3 years ago
If each data is increased by a constant K then find it's mean ?? answer fast pleaseeeeeeeeeee​
MArishka [77]

Answer:

The mean is also increased by the constant k.

Step-by-step explanation:

Suppose that we have the set of N elements

{x₁, x₂, x₃, ..., xₙ}

The mean of this set is:

M = (x₁ + x₂ + x₃ + ... + xₙ)/N

Now if we increase each element of our set by a constant K, then our new set is:

{ (x₁ + k), (x₂ + k), ..., (xₙ + k)}

The mean of this set is:

M' = ( (x₁ + k) + (x₂ + k) + ... + (xₙ + k))/N

M' = (x₁ + x₂ + ... + xₙ + N*k)/N

We can rewrite this as:

M' = (x₁ + x₂ + ... + xₙ)/N + (k*N)/N

and  (x₁ + x₂ + ... + xₙ)/N was the original mean, then:

M' = M + (k*N)/N

M' = M + k

Then if we increase all the elements by a constant k, the mean is also increased by the same constant k.

6 0
3 years ago
G(n)=-4n+2; find g(8)<br>​
yarga [219]

Answer:

-30

Step-by-step explanation:

In g(8) the 8 = n.  So, substitute 8 in for n in the expression -4n + 2

g(8)  =  -4(8) + 2 = -32 + 2 = -30

4 0
3 years ago
Read 2 more answers
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