3 years ago

What is the solution to log 8x = 3?

Mathematics

1 answer:

Aleks04 [339]3 years ago

8 0

answer : 3/8 or .375

8x=3

divide both sides by 8

x=3/8 or .375

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Write 11 times 47 using the distributive property. Then simplify.

Simora [160]

Distributive property is in the form of:

a (b+c) = ab + bc

In this case, we try writing 47 as:

47 = 50-3 or 47 = 40+7

Therefore:

11 x 47 = 11 x (50-3) = 11 x 50 - 11 x 3 = 550 - 33 = 517

or

11 x 47 = 11 x (40+7) = 11 x 40 + 11 x 7 = 440 + 77 = 517

5 0

4 years ago

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If the sum of 4040 consecutive integer numbers is 2020, find out the absolute difference between the first number and the last n

bearhunter [10]

Let $x$ be the smallest of the consecutive integers summing to 2020. Then the largest integer in the sum is $x+4039,$ so our answer is $\boxed{4039}.$

For completeness, though, let's solve for the value of $x$ that satisfies the conditions of the problem. Recall that the sum of an arithmetic series with first term $a_1,$ last term $a_n,$ and $n$ terms, is $\frac{n(a_1+a_n)}{2}.$ Plugging in our known values gives us the equation $\frac{4040(2x+4039)}{2}=2020,$ which simplifies to $2x+4039=1.$ Thus, $x=-2019,$ so the 4040 consecutive integers are $-2019,-2018,\dots,-1,0,1,\dots,2018,2019,2020.$ Notice how everything except the $2020$ cancels out!