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lions [1.4K]
3 years ago
12

For someone whos a Ambitious and needs Brainliest's points this is for you

Mathematics
2 answers:
maksim [4K]3 years ago
8 0

Answer: How my I help you?

Step-by-step explanation: Math, History, Spanish?

Anton [14]3 years ago
7 0

Step-by-step explanation:

<em><u>A peptide bond is an amide type of covalent chemical bond linking two consecutive alpha-amino acids from C1 of one alpha-amino acid and N2 of another, along a peptide or protein chain.</u></em>

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3/5 of your teammates want to wear red jerseys. 1/4 of those teammates also want to wear red pants. What fraction want to wear r
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Answer:

3/20

Step-by-step explanation:

1/4 of 3/5= 3/20

hope its clear

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6. Roy hit 3 less than 4 times the number of balls during baseball practice than Joe did. Together the boys hit 52 balls. How ma
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Joe hit ten balls :)

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3 years ago
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Which of the following number lines represents the solution to x - 5 ≥ -2?
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This one is your answer hope this helps

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3 years ago
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Let f be defined by the function f(x) = 1/(x^2+9)
riadik2000 [5.3K]

(a)

\displaystyle\int_3^\infty \frac{\mathrm dx}{x^2+9}=\lim_{b\to\infty}\int_{x=3}^{x=b}\frac{\mathrm dx}{x^2+9}

Substitute <em>x</em> = 3 tan(<em>t</em> ) and d<em>x</em> = 3 sec²(<em>t </em>) d<em>t</em> :

\displaystyle\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\frac{3\sec^2(t)}{(3\tan(t))^2+9}\,\mathrm dt=\frac13\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\mathrm dt

=\displaystyle \frac13 \lim_{b\to\infty}\left(\arctan\left(\frac b3\right)-\arctan(1)\right)=\boxed{\dfrac\pi{12}}

(b) The series

\displaystyle \sum_{n=3}^\infty \frac1{n^2+9}

converges by comparison to the convergent <em>p</em>-series,

\displaystyle\sum_{n=3}^\infty\frac1{n^2}

(c) The series

\displaystyle \sum_{n=1}^\infty \frac{(-1)^n (n^2+9)}{e^n}

converges absolutely, since

\displaystyle \sum_{n=1}^\infty \left|\frac{(-1)^n (n^2+9)}{e^n}\right|=\sum_{n=1}^\infty \frac{n^2+9}{e^n} < \sum_{n=1}^\infty \frac{n^2}{e^n} < \sum_{n=1}^\infty \frac1{e^n}=\frac1{e-1}

That is, ∑ (-1)ⁿ (<em>n</em> ² + 9)/<em>e</em>ⁿ converges absolutely because ∑ |(-1)ⁿ (<em>n</em> ² + 9)/<em>e</em>ⁿ| = ∑ (<em>n</em> ² + 9)/<em>e</em>ⁿ in turn converges by comparison to a geometric series.

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3 years ago
Steven, Lisa and Mark want to buy a pizza. Steven said he could pay twice as much as Lisa. Mark said he could pay the remaining
34kurt

Answer:

$5

Step-by-step explanation:

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