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KengaRu [80]
3 years ago
9

It is reported that the average woman's hair grows a quarter of an inch per month. A new vitamin company believes that women who

take its vitamin daily will have increased hair growth. Before putting its product on the market, the company plans on running a test on the effectiveness of the vitamins. Which null and alternative hypotheses should the company use for this study
Mathematics
1 answer:
Basile [38]3 years ago
4 0

Answer:

H0: u = 0.25 (Null)

Ha: u > 0.25 (Alternate)

Step-by-step explanation:

Hypothesis is written following the rules below:

i) 2 hypotheses are formed  in a way that complement of one is claim in the other.

ii) H₀ - the null hypothesis , is the boring hypothesis which claims that things are expected

iii) H₁ -the alternative hypothesis states a claim against null. It always contain the strict inequality signs : less than sign (<), greater than sign (>)and not equal to sign (≠).

Here, we are testing if the mean is less than 0.25 inch

We thus have :

H₀ : u = 0.25 as the null hypothesis and

H₁ : u > 0.25 as the alternative hypothesis

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Find the quotient of (11 ^ 18)/(11 ^ 3)
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Answer:

The first choice, 11^{15}.

Step-by-step explanation:

The numerator, 11^{18}, is equivalent to eighteen "11" multiplied together:

11^{18} = \underbrace{11 \times 11 \times 11 \times 11 \times \cdots \times 11 \times 11}_{\text{$18$ in total}}.

On the other hand, the denominator, 11^{3}, is equivalent to three "11" multiplied with one another:

11^{3} = 11 \times 11 \times 11.

Dividing 11^{18} by 11^{3} would eliminate three "11" from the numerator:

\begin{aligned}& \frac{11^{18}}{11^{3}} \\ =\; & \frac{(11 \times 11 \times 11) \times \overbrace{11 \times \cdots \times 11}^{\text{$(18 - 3)$ in total}}}{(11 \times 11 \times 11)} \\ =\; & \overbrace{11 \times \cdots \times 11}^{\text{$15$ in total}} \\ =\; & 11^{15}\end{aligned}.

In general, dividing an expression by y^{b} (y \ne 0) is equivalent to multiplying that expression by y^{-b}.

For example, in this question, dividing 11^{18} by 11^{3} would be equivalent to multiplying 11^{18}\! by 11^{-3}. In other words:

\begin{aligned}& \frac{11^{18}}{11^{3}} \\ =\; & 11^{18} \times 11^{-3} \\ =\; & 11^{18 - 3} \\ =\; & 11^{15}\end{aligned}.

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Step-by-step explanation:

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