Can someone give me brainlyist plz

Mathematics

1 answer:

natali 33 [55]3 years ago

7 0

Answer:

You can give me brainliest if you want

Step-by-step explanation:

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I need help and I can’t find any sadly. Help!!

Tamiku [17]

1. Given

2. Combine like terms

3. Subtraction POE (Property of Equality)

5 0

2 years ago

How many solutions can be found for the equation 4z + 2(z – 4) = 3z + 11? (4 points)

zlopas [31]

I hope this helps you

4z+2.z-4.2=3z+11

4z-3z+2z=11+8

3z=19

z=19/3

one solution

3 0

3 years ago

Read 2 more answers

Hi, help with question 18 please. thanks

Vadim26 [7]

Answer:

See Below.

Step-by-step explanation:

We are given the equation:

$\displaystyle y^2 = 1 + \sin x$

And we want to prove that:

$\displaystyle 2y\frac{d^2y}{dx^2} + 2\left(\frac{dy}{dx}\right) ^2 + y^2 = 1$

Find the first derivative by taking the derivative of both sides with respect to <em>x: </em>

<em /> $\displaystyle 2y \frac{dy}{dx} = \cos x$ <em />

Divide both sides by 2<em>y: </em>

<h3><em /> $\displaystyle \frac{dy}{dx} = \frac{\cos x}{2y}$ <em /></h3>

<em />

Find the second derivative using the quotient rule:

$\displaystyle \begin{aligned} \frac{d^2y}{dx^2} &= \frac{(\cos x)'(2y) - (\cos x)(2y)'}{(2y)^2}\\ \\ &= \frac{-2y\sin x-2\cos x \dfrac{dy}{dx}}{4y^2} \\ \\ &= -\frac{y\sin x + \cos x\left(\dfrac{\cos x}{2y}\right)}{2y^2} \\ \\ &= -\frac{2y^2\sin x+\cos ^2 x}{4y^3}\end{aligned}$