Answer: 49.85%
Step-by-step explanation:
Given : The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped ( normal distribution ) and has a mean of 61 and a standard deviation of 9.
i.e.
and 
To find : The approximate percentage of lightbulb replacement requests numbering between 34 and 61.
i.e. The approximate percentage of lightbulb replacement requests numbering between 34 and
.
i.e. i.e. The approximate percentage of lightbulb replacement requests numbering between
and
. (1)
According to the 68-95-99.7 rule, about 99.7% of the population lies within 3 standard deviations from the mean.
i.e. about 49.85% of the population lies below 3 standard deviations from mean and 49.85% of the population lies above 3 standard deviations from mean.
i.e.,The approximate percentage of lightbulb replacement requests numbering between
and
= 49.85%
⇒ The approximate percentage of lightbulb replacement requests numbering between 34 and 61.= 49.85%
He walked 45 mins and burned 250 i think hope i helped
Answer:
86+18
Step-by-step explanation:
Use the properties of 45-45-90 triangles to get a side length of 18 for the 2 legs of the isosceles triangle. Then add 43+18, which is the shorter length of the rectangle, +25, which is the longer edge, +18
. The answer is now 86+18
.
Answer:
see below PLEASE GIVE BRAINLIEST
Step-by-step explanation:
549 - 36.5 = 512.5mb were trf
512.5/125 = 4.1mb per second
Answer:
y=3x-4
Step-by-step explanation: