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3 years ago

Point Q is the image of Q(4-6) under a translation by 1 unit to the right

Mathematics

1 answer:

inessss [21]3 years ago

5 0

Answer:

The image of Q(4,-6) under a translation by 1 unit to the right then the new coordinate point R( 5 , -6)

Step-by-step explanation:

Explanation:-

Given image Q( 4, -6)

Type of transformation change to co-ordinate point

a) Horizontal translation left

'C' units (x, y) ⇒ (x- c, y)

b) Horizontal translation right 'C' units (x, y)⇒( x +c ,y )

c) vertical translation up 'd' units (x, y)⇒( x ,y + d )

d) vertical translation down 'd' units (x, y)⇒( x ,y - d )

Now we will use Horizontal translation right 'C' units

image of Q(4-6) under a translation by 1 unit to the right

Q( 4 , -6) ⇒ The new image R( 4+1 ,-6)

The image of Q(4-6) under a translation by 1 unit to the right then the new coordinate point R( 5 , -6)

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Dominic earns $18 an hour plus $25 an hour for every hour of overtime. Overtime hours are any hours more than 35 hours for the w

alexgriva [62]

Part A: (no overtime) E = 18x. Please note that x cannot exceed 35, thus E cannot exceed $630.

Part B: T = 25y + 18x where x = 35 hours. Thus, T = 25y + 630.

Part C: T = $730. 730 = 630 + 25y. Subtract 630 from both sides. 100 = 25y. Divide both sides by 25. y = 4. This is the number of overtime hours -- remember that Dominic has already worked 35 hours non-overtime. 35 + 4 = $730.

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3 years ago

What bedmass question ends with 210

spayn [35]

Answer:

33-9+40-(30+15) =

33-9+40+25-(30+15) =

3+21 x 6-(24-4) =

3+21 x 6-(24-4) x 2 =

(62 ÷ 2 – 3) x 3 +6 =

(62 ÷ 2 – 3) x 3 +6 x 2=

0.3+0.8+0.2=

30+30×0+1=

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Given quadrilateral EFGH at e(-4,7) f(8,4) G(t,-5) and h(-7,-1) using coordinate geometry prove EFGH is a rectangle

Tcecarenko [31]

The above question was not properly written.

Complete Question

Given quadrilateral EFGH with vertices at E(-4,8), F(8,4), G(5,-5) and H(-7,-1), prove using coordinate geometry that EFGH is a rectangle.

Answer:

Quadrilateral EFGH is a rectangle.l because:

EF = GH and FG = EH

Step-by-step explanation:

The formula for coordinate geometry is given as :

√(x2 - x1)² + (y2 - y1)² when we have coordinates: (x1, y1) and (x2 , y2)

For the quadrilateral EFGH with given coordinates above to be a rectangle,

EF = GH

FG = EH

Hence:

For side EF

E(-4,8), F(8,4)

= √(8 - (-4))² + (4 - 8)²

= √12² + -4²

= √144 + 16

= √160 units

For side FG

F(8,4), G(5,-5)

=√(5 - 8)² + (-5 - 4)²

= √-3² + -9²

= √9 + 81

= √90 units

For Side GH

G(5,-5) , H(-7,-1)

= √(-7 - 5)² + (-1 - (-5))²

= √-12² + 4²

= √144 + 16

= √160 units

For side EH

E(-4,8), H(-7,-1)

= √(-7 -(-4))² +(-1 - 8)²

= √-3² + -9²

= √9 + 81

= √90 units

From the above calculation, we can see that truly,

EF = GH

FG = EH

Therefore, quadrilateral EFGH is a rectangle.

6 0

3 years ago

1.012 - 0.809 +2.75<br><br>give me the answer

meriva

Answer:

2.953

Step-by-step explanation:

Following the order of operations, work from left to right for addition/subtraction.

Subtraction:

$\begin{array}{r r r r r} ^0\diagup\!\!\!\!1 &. & ^10 & ^0\diagup\!\!\!\!1&^1 2\\ -\quad0&.&8&0&9\\\cline{1-5}0&.&2&0&3\\\cline{1-5} \end{aligned}$

Addition:

$\begin{array}{r c c c r} 0 & . & 2&0&3\\ + \:\:2 &.& 7 & 5\\\cline{1-5}2&.&9&5&3\\\cline{1-5} \end{aligned}$

Therefore, the solution is 2.953

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2 years ago

Read 2 more answers

Anyone know this?need help ASAP

slava [35]

Answer:

Step-by-step explanation:

I used Toa to figure it out. First I did Tan(32) times 13 and got 45.

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3 years ago