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wolverine [178]
2 years ago
11

Point Q is the image of Q(4-6) under a translation by 1 unit to the right

Mathematics
1 answer:
inessss [21]2 years ago
5 0

Answer:

The  image of Q(4,-6) under a translation by 1 unit to the right then the new coordinate point R( 5 , -6)

Step-by-step explanation:

Explanation:-

Given image Q( 4, -6)

Type of transformation                                    change to co-ordinate point

a) Horizontal translation left

'C' units                                                                        (x, y)  ⇒   (x- c, y)

b) Horizontal translation right 'C' units                   (x, y)⇒( x +c ,y )

c) vertical translation up 'd' units                            (x, y)⇒( x  ,y + d )

d)  vertical translation down 'd' units                        (x, y)⇒( x  ,y - d )

     

Now we will use Horizontal translation right 'C' units    

image of Q(4-6) under a translation by 1 unit to the right

Q( 4 , -6)   ⇒ The new image R( 4+1 ,-6)

The  image of Q(4-6) under a translation by 1 unit to the right then the new coordinate point R( 5 , -6)

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Determine how many solutions each equation has without using inverse operations. Explain your reasoning for each.
GuDViN [60]

Answer:

  an infinite number

Step-by-step explanation:

The left side of the equation is a restatement of the right side of the equation. It is true for all values of x. There are an infinite number of solutions.

7 0
3 years ago
The cost of a large cake at a bakery is $21.00. The cost of a small cake is
Alchen [17]

Answer:

The Subtotal cost of all the cakes before tax and delivery

Step-by-step explanation:

(21x+8.25y)

21 is the price of 1 large cake and X is the number of cakes they want to purchase not counting tax and delivery fee.

8.25 is the price of 1 small cake and Y is the number of cakes they want to purchase not counting tax and delivery fee.

8 0
2 years ago
Written as a simplified polynomial in standard form, what is the result when
arlik [135]

8x3 + 10x2 – 8x + 1

: Hope this helps :)
5 0
3 years ago
We are interested in the dimensions of a certain rectangle. this rectangle has length twice the side of the square and width thr
Mila [183]
Area of square = s^2
Area of Rectangle = lw
l = 2s

w+3 = s
solve for w, w=s-3
Now we have l and w.
Plug both into area of rectangle formula so: (2s)(s-3)
Since both areas are equal set both equations equal to each other:
(2s)(s-3)=s^2
Now simplify
2s^2-6s=s^2
s^2-6s=0, Solve for s.
Factor polynomial. s(s-6)=0 , s can be equal to 0 or 6. HOWEVER, you cannot have a side length of 0 therefore the side length has to be 6.
Now plug in s for the length formula for the rectangle:
l = 2s so... l = 2(6) so length of rectangle = 12.
Now plug in s for the width formula for the rectangle:
w+3=s so... w+3=6 so width of rectangle = 3.
Now the dimensions of the rectangle are 12 by 3. 12 being length and 3 width.
To CHECK:
Find area of rectangle:
A=lw so A=3 times 12 so A=36
Find area of square:
We know the side is equal to 6 so
A=s^2 so 6^2 = 36
The areas are equal that verifies the answer of 12 by 3.
8 0
3 years ago
Please answer!!!! will make brainliest!!!
hammer [34]

Answer:

B

Step-by-step explanation:

1.

  • 3(x+3) - 2 < 4
  • 3x + 9 -2 < 4
  • 3x < 4-7
  • 3x < - 3
  • x < -1
  • x = (-oo, -1)

2.

  • 1 - x ≤ -1
  • - x ≤ -1 - 1
  • -x ≤ -2
  • x ≥ 2
  • x = [2, +oo)

Correct choice is B.

7 0
3 years ago
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