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Oksanka [162]
3 years ago
8

CAN SOMEONE HELP REALLY QUICK?

Mathematics
1 answer:
attashe74 [19]3 years ago
8 0
204 in^3 
Hope this helps! :)
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1x10 to the fifth power over 4x10 to the negative faith power given on scientific notation
MissTica

Answer:

2.5*10^{8}

Step-by-step explanation:

<u><em>The correct question is</em></u>

1x10 to the fifth power over 4x10 to the negative fourth power given on scientific notation

we know that

To divide two numbers in scientific notation, divide their coefficients and subtract their exponents.

we have

\frac{1*10^{5}}{4*10^{-4}}=(\frac{1}{4})*10^{5+4} =0.25*10^{9}= 2.5*10^{8}

8 0
3 years ago
The 12th term in a sequence with a common difference of-9 is -106. which of the following formulas can be used to represent this
Effectus [21]

Answer:

T12=a-99=106

Step-by-step explanation:

that's the answer

6 0
2 years ago
Which of the following is the shape of a cross-section of the figure shown
Aliun [14]

Answer:

B. Pyramid

Step-by-step explanation:

3 0
3 years ago
Use the given minimum and maximum data​ entries, and the number of​ classes, to find the class​ width, the lower class​ limits,
Gennadij [26K]

Using proportions and the information given, it is found that:

  • The class width is of 14.375.
  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

-------------------------

  • Minimum value is 19.
  • Maximum value is of 134.
  • There are 8 classes.
  • The classes are all of equal width, thus the width is of:

W = \frac{134 - 19}{8} = 14.375

-------------------------

The intervals will be of:

19 - 33.375

33.375 - 47.750

47.750 - 62.125

62.125 - 76.500

76.500 - 90.875

90.875 - 105.250

105.250 - 119.625

119.625 - 134.

  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

A similar problem is given at brainly.com/question/16631975

6 0
3 years ago
X^2 + y^2 = 8<br> X-y=0<br> Select all of the following that are solutions to the system shown
ludmilkaskok [199]

X^2 + y^2 = 8
X-y=0 so x = y

replace x = y into X^2 + y^2 = 8

y^2 + y^2 = 8

2y^2 = 8

y^2 = 8/2

y^2 = 4

y = - 2 and y = 2

because x = y

so x = - 2 and x = 2

solutions:

x= - 2 and x = + 2

y= - 2 and y = + 2

5 0
3 years ago
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