3 years ago

CAN SOMEONE HELP REALLY QUICK?

Mathematics

1 answer:

attashe74 [19]3 years ago

8 0

204 in^3
Hope this helps! :)

You might be interested in

Which equation is equivalent to 2/3x-5/6=-5/12x+1/4

umka21 [38]

Answer:

x = 1

Step-by-step explanation:

$\frac{2}{3} x - \frac{5}{6} = - \frac{5}{12} x + \frac{1}{4} \\ \frac{2}{3}x + \frac{5}{12} x = \frac{1}{4} + \frac{5}{6} \\ \frac{8}{12} x + \frac{5}{12}x = \frac{3}{12} + \frac{10}{12} \\ \frac{13}{12} x = \frac{13}{12} \\ x = 1$

6 0

3 years ago

Read 2 more answers

Suppose a and b are both non zero real numbers. Find real numbers c and d such that 1/a+ib= c+id

Thepotemich [5.8K]

$\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}$

Explanation

$\frac{1}{a+bi}=c+di$

Step 1

multiplicate by the conjugate

$\begin{gathered} \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(bi)^2} \\ \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(-b^2)}=\frac{a-bi}{a^2+b^2} \end{gathered}$

notice that

$\begin{gathered} \frac{1}{a+bi}=\frac{a-bi}{a^2+b^2}=\frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i \\ \frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i=c+di \\ so \\ \end{gathered}$ $\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}$

I hope this helsp you

6 0

1 year ago

Find distance between parallel lines given equations in 3d

Lena [83]

Does it have an image?

6 0

3 years ago

Use the graph to find the solution to this system of linear equations. y = 58x + 18 and y = -12x – 1

vfiekz [6]

Answer:

Step-by-step explanation: do you have any choices